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3 years ago

What’s the unit rate of 75:25

Mathematics

1 answer:

Alex73 [517]3 years ago

3 0

Answer:

Step-by-step explanation:

$75:25 \\ \frac{75}{25} : \frac{25}{25} \\ 3:1$

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64 is 4 times the difference between Sarah's age, aaa, and 44. Assume Sarah is older than 44. How would I write this as an equat

jeka94

Answer:

4(aaa - 44) = 64

Step-by-step explanation:

I think this is right.

4 0

3 years ago

Plz help me!!!!!i need to get this correct plz help!!!

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Answer:

Yes

Step-by-step explanation:

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3 0

3 years ago

-4x + 7 = 2y - 3<br> y-intercept:<br><br> x intercept:

pantera1 [17]

Answer:

x-intercept: $\bigg(\frac{5}{2}, \:0\bigg)$

y-intercept: $(0,\:5)$

Step-by-step explanation:

To find the x-intercept, substitute in $0$ for $y$ and solve for $x$ .

$-4x + 7 = 2y - 3$

$-4x+7=2\left(\bold{0}\right)-3$

Simplify 2(0): $-4x+7=2\cdot \:0-3$

Subtract 0 - 3 = -3: $-4x+7=-3$

Subtract 7 from both sides: $-4x+7-7=-3-7$

Simplify: $-4x=-10$

Divide both sides by -4 $\frac{-4x}{-4}=\frac{-10}{-4}$

$\bold{x=\frac{5}{2}}$

To find the y-intercept, substitute in $0$ for $x$ and solve for $y$ .

$-4x + 7 = 2y - 3$

$-4(\bold{0})+7=2y-3$

Switch sides: $y-3=-4\left(0\right)+7$

Simplify -4(0): $2y-3=-0+7$

Add 3 to both sides: $2y-3+3=7+3$

Simplify: $2y=10$

Divide both sides by 2: $\frac{2y}{2}=\frac{10}{2}$

$\bold{y=5}$

3 0

2 years ago

PLEASE HELP! The table shows the number of championships won by the baseball and softball leagues of three youth baseball divisi

Irina18 [472]

Answer:

Question 1: $P ( B | Y ) = \frac{ P ( B and Y)}{ P (Y)} = \frac{ \frac{2}{16}}{ \frac{4}{16}} = \frac{1}{2}$

Question 2:

A. $P ( Y | B ) = \frac{ P(Y and B) }{ P(B) } = \frac{ \frac{2}{16} }{ \frac{6}{16} } = \frac{1}{3}$

B. $P( Z | B ) = \frac{ P ( Z and B)}{ P (B)}= \frac{ \frac{1}{16} }{ \frac{6}{16} } = \frac{1}{6}$

C. $P((Y or Z)|B) = \frac{ P ((Y or Z) and B)}{P(B)}= \frac{ \frac{3}{16}}{ \frac{6}{16}}= \frac{1}{2}$

Step-by-step explanation:

Conditional probability is defined by

$P(A|B)= \frac{P(A and B)}{P(B)}$

with P(A and B) beeing the probability of both events occurring simultaneously.

Question 1:

B: Baseball League Championships won, beeing

$P ( B ) = \frac{ 6 }{16}$

Y: Championships won by the 10 - 12 years old, beeing

$P ( Y)= \frac{ 4 }{ 16 }$

then

P( B and Y)= \frac{ 2 }{ 16 }[/tex]

By definition,

$P ( B | Y ) = \frac{ P ( B and Y)}{ P (Y)} = \frac{ \frac{2}{16} }{ \frac{4}{16} } = \frac{1}{2}$

Question 2.A:

Y: Championships won by the 10 - 12 years old, beeing

$P ( Y)= \frac{ 4 }{ 16 }$

B: Baseball League Championships won, beeing

$P ( B ) = \frac{ 6 }{16}$

then

P( B and Y)= \frac{ 2 }{ 16 }[/tex]

By definition,

$P ( Y | B ) = \frac{ P(Y and B) }{ P(B) } = \frac{ \frac{2}{16} }{ \frac{6}{16} } = \frac{1}{3}$

Question 2.B:

Z: Championships won by the 13 - 15 years old, beeing

$P ( Z)= \frac{ 1 }{ 16 }$

B: Baseball League Championships won, beeing

$P ( B ) = \frac{ 6 }{16}$

then

P( Z and B)= \frac{ 1 }{ 16 }[/tex]

By definition,

$P( Z | B ) = \frac{ P ( Z and B)}{ P (B)}= \frac{ \frac{1}{16} }{ \frac{6}{16} } = \frac{1}{6}$

Question 3.B

Y: Championships won by the 10 - 12 years old, beeing

$P ( Y)= \frac{ 4 }{ 16 }$

Z: Championships won by the 13 - 15 years old, beeing

$P ( Z)= \frac{ 1 }{ 16 }$

then

$P (Y or Z) = P(Y) + P(Z) = \frac{6}{16}$

B: Baseball League Championships won, beeing

$P ( B ) = \frac{ 6 }{16}$

$P((YorZ) and B)= \frac{3}{16}$

By definition,

$P((Y or Z)|B) = \frac{ P ((Y or Z) and B)}{P(B)}= \frac{ \frac{3}{16}}{ \frac{6}{16}}= \frac{1}{2}$

3 0

3 years ago

What is the surface area of this figure?

Mkey [24]

Answer:

100

Step-by-step explanation:

hope this helped

stay safe

brainliest is appreciated only 1more to level up please help :)))

8 0

3 years ago