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kupik [55]
2 years ago
12

Any device that performs single conversion is ____​

Computers and Technology
1 answer:
andrew-mc [135]2 years ago
5 0

Answer:

modulator

Explanation:

A modulator is a device that performs modulation.

(Single conversation)

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Assume that a gallon of paint covers about 350 square feet of wall space. Create an application with a main() method that prompt
Makovka662 [10]

Answer:

<em>C++</em>

#include <iostream>

#include <cmath>

using namespace std;

///////////////////////////////////////////////////////////////////////

int noOfGallons(int wallArea) {

   int gallon = 350;

   int gallon_price = 32.0;

   float total_price = 0.0;

   ///////////////////////////////////////////

   float noOfGallons = (float)wallArea/(float)gallon;

   printf("No of gallons needed %.2f", noOfGallons);

   cout<<endl;

   //////////////////////////////////////////

  total_price = noOfGallons*gallon_price;

   return round(total_price);

}

int wallArea(int length, int width, int height) {

   int wall_area = length*width;

   int total_price = noOfGallons(wall_area);

}

///////////////////////////////////////////////////////////////////////

int main() {

   int length, width, height;

   ///////////////////////////////////////////

   cout<<"Enter length: ";

   cin>>length;

   

   cout<<"Enter width: ";

   cin>>width;

   

   cout<<"Enter height: ";

   cin>>height;

   

   cout<<endl;

   ///////////////////////////////////////////

   int total_price = wallArea(length, width, height);

  cout<<"Total price: $"<<total_price;

   ///////////////////////////////////////////

   return 0;

}

5 0
2 years ago
4. Computer processing work that is split between a desktop computer and a more powerful computer that processes and stores shar
jeyben [28]

Answer:

A. client/server

Explanation:

Beacuse a Server or a client is what hold data for big companies like google and microsoft

7 0
3 years ago
Integers and booleans. Write a program RightTriangle that takes three int command-line arguments and determines whether they con
icang [17]

Answer:

<em>The programming language is not stated;</em>

<em>I'll answer using C++</em>

#include<iostream>

#include<cmath>

using namespace std;

int main()

{

int side1, side2, side3;

cout<<"Enter the three sides of the triangle: "<<endl;

cin>>side1>>side2>>side3;

if(side1<=0 || side2 <= 0 || side3 <= 0) {

 cout<<"Invalid Inputs";

}

else {

 if(abs(pow(side1,2) - (pow(side2,2) + pow(side3, 2)))<0.001) {

  cout<<"Right Angled";

 }

 else if(abs(pow(side2,2) - (pow(side1,2) + pow(side3, 2)))<0.001) {

  cout<<"Right Angled";

 }

 else if(abs(pow(side3,2) - (pow(side2,2) + pow(side1, 2)))<0.001) {

  cout<<"Right Angled";

 }

 else {

  cout<<"Not Right Angled";

 }

}

return 0;

}

Explanation:

The following line declares the three variables

int side1, side2, side3;

The next line prompts user for input of the three sides

cout<<"Enter the three sides of the triangle: "<<endl;

The next line gets user input

cin>>side1>>side2>>side3;

The following if condition checks if any of user input is negative or 0

<em> if(side1<=0 || side2 <= 0 || side3 <= 0) { </em>

<em>  cout<<"Invalid Inputs"; </em>

<em> } </em>

If otherwise

else {

The following if condition assumes that side1 is the largest and test using Pythagoras Theorem

<em>if(abs(pow(side1,2) - (pow(side2,2) + pow(side3, 2)))<0.001) { </em>

<em>   cout<<"Right Angled"; </em>

<em>  } </em>

The following if condition assumes that side2 is the largest and test using Pythagoras Theorem

<em>  else if(abs(pow(side2,2) - (pow(side1,2) + pow(side3, 2)))<0.001) { </em>

<em>   cout<<"Right Angled"; </em>

<em>  } </em>

The following if condition assumes that side3 is the largest and test using Pythagoras Theorem

<em>  else if(abs(pow(side3,2) - (pow(side2,2) + pow(side1, 2)))<0.001) { </em>

<em>   cout<<"Right Angled"; </em>

<em>  } </em>

If none of the above conditions is true, then the triangle is not a right angles triangle

<em>  else { </em>

<em>   cout<<"Not Right Angled"; </em>

<em>  } </em>

}

return 0;

Download cpp
4 0
3 years ago
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