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Nimfa-mama [501]
3 years ago
11

A candy store sells mints in 1/4, 1/2 , and 3/4 lb packages. John purchases several packages of each weight.

Mathematics
1 answer:
KiRa [710]3 years ago
3 0

For this problem, just multiply the fractions by the amount of packages purchased.

6 * 1/4 = 1 1/2

8 * 1/2 = 4

7 * 3/4 = 5 1/4

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D) 300 tiles

Step-by-step explanation:

20 * 15 = 300



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The width of a rectangle measures (26 8c) centimeters, and its length measures
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POINTS :D

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son4ous [18]

Answer:

A.       { [ (12*2 ) + ( 18*2 ) + (13*4 ) ] (3.50) } = x

B.       $392 is the amount George will pay

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6 0
4 years ago
Which equations are true for x = –2 and x = 2? Select two options x2 – 4 = 0 x2 = –4 3x2 + 12 = 0 4x2 = 16 2(x – 2)2 = 0
Svetllana [295]

The equation x^{2} -4=0~~and~~4x^2=16 are true for  x = -2 and x = 2.

The given equations are given as:

x^2-4=0\\\\x^2=-4\\\\3x^2+12=0\\\\4x^2=16\\\\2(x-2)^2=0

We need to select two equations that are true for x = -2 and x = 2.

<h3>What are the solutions to an equation ?</h3>

The solutions of an equation are the values that satisfy the given equation or make the equation true when substituted for unknowns in the equations.

Example:

x - 2 = 2

Here the solution for x - 2 = 2 is 4 because x = 4 will make the equation true.

4 - 2 = 2

2 = 2

Let's find the solutions for each equation.

1.

x^2 - 4=0

x^{2} = 4

x = \sqrt{4} = ± 2

x = = 2 and x = -2

2.

x^2 =-4

x = \sqrt{-4}

x = \sqrt{-1 \times 4} = \sqrt{-1}\times\sqrt{4}

x = ± 2 \sqrt{-1}

x = 2i and x = -2i         where i = \sqrt{-1}

3.

3x^{2} + 12  = 0

x^{2} = -12 / 3 = -4

x = \sqrt{-1} \sqrt{4}

x = ± 2\sqrt{-1}

x = 2i and x = -2i

4.

4x^{2} = 16

x^{2} = 16 / 4

x^{2} = 4

x = \sqrt{4}

x = ±2

x = 2 and x = -2

5.

2(x-2)^2 = 0

(x-2)^2 = 0

x - 2 = 0

x = 2.

Thus the equation x^{2} -4=0~~and~~4x^2=16 have solutions x = -2 and x = 2.

Learn more about solutions of equations here:

brainly.com/question/14506845

#SPJ1

4 0
2 years ago
raj and his sister zia are both at secondary school. Raj is three years older than zia. the sum of the squares of their ages is
Cerrena [4.2K]

Let Zia's age be = x years

Raj is three years older than Zia, so Raj's age = x+3 years

As the sum of the squares of their ages is 369, so

x^{2}+(x+3)^{2}=369

x^{2}+x^{2}+6x+9=369

2x^{2}+6x+9=369

2x^{2}+6x-360=0

Factoring 2 out we have,

x^{2}+3x-180=0

Now solving this equation,

x^{2}+15x-12x-180=0

x(x+15)-12(x+15)

(x+15)(x-12)

x=-15 and x=12

Neglect the negative value as x cannot be negative

So x=12

Hence, Zia's age is 12 years and

Raj's age is 12+3 = 15 years


4 0
3 years ago
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