A. Area of ABCD - Area of DGA = Area of DEFG
s^2 - 1/2bh = s^2
(5)^2 - 1/2(4)(3) = (3)^2
25 - 1/2(12) = 9
25 - 24 = 9
1 not equal to 9
B. Area of ABCD - Area of GHIA = Area of DGA
s^2 - s^2 = 1/2bh
(5)^2 - (4)^2 = 1/2(4)(3)
25 - 16 = 1/2(12)
9 not equal to 6
C. Area of ABCD + Area of DGA = Area of GHIA
s^2 + 1/2bh = s^2
(5)^2 + 1/2(4)(3) = (4)^2
25 + 1/2(12) = 16
25 + 6 = 16
31 not equal to 16
D. Area of DEFG + Area of GHIA = Area of ABCD
s^2 + s^2 = s^2
(3)^2 + (4)^2 = (5)^2
9 + 16 = 25
25 = 25
The answer is D.
Answer:
height = 7.78 mm, while base = 31.11
Step-by-step explanation:
First, create the equation "4x^2=242." After doing this, solve for x. Once you do this, you will find x as 7.78. The x value is your height. To find the base, multiply height by 4.
Answer:
Causation
Step-by-step explanation:
Studying better prepares you for a test, getting you better grades.
Answer:
B
Step-by-step explanation:
Equation of line 1:
Choose two points : (-1, 0) & (0,2)
y -intercept = b = 2
y = mx+ 2
Plugin the values of the points ( -1 , 0) in the above equation
0 = -1m + 2
-2 = -m
m = 2
Equation of line 1 : y = 2x + 2
Equation of line 2:
(5,0) & (0,5)
y-intercept = b = 5
y = mx +b
y = mx + 5
Plugin the value of points (5 , 0) in the above equation
0 = 5m + 5
-5 = 5m
-5/5 = m
m = -1
Equation of line 2: y = -x + 5
Conclusion: 2x + 2 = -x + 5
A dime weighs 2.268 grams, and a quarter weighs 5.670 grams.
