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vampirchik [111]

3 years ago

10

Diagonals of an isosceles trapezoid are perpendicular to each other and the sum of the lengths of its bases is 2a. What is its

area?
PLEASE HELP!!!!!

2 answers:

sergey [27]3 years ago

7 0

Area= a*height
the formula for an isosceles trapezoid is 1/2(base1+base2)*height. 1/2 base 2 and 2a will simplify to a base length of a. a times height or a*height

ira [324]3 years ago

5 0

It's a^2

the altitude is a
so....

(b1+b2)/2*h=
(2a)/2*a
a*a=a^2

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Given the rational expression: $\frac{2x + 3}{x^2 - 5x + 4}$ , to express this in simplified form, we would need to apply the concept of partial fraction.

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Substituting x = 4 in $2x + 3 = A(x - 4) + B(x - 1)$

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$B = \frac{11}{3}$

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$2(1) + 3 = A(1 - 4) + B(1 - 1)$

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<h3 /><h3 />

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