The correct answer is C. neither congruent nor similar.
Given that △ABC is transformed to △A'B'C' such that AB = A'B'.
We know that:
For triangles to be similar, all three angles must be same(AAA property) or all three sides must be in same proportion(SSS property) or two sides must be in same proportion and the included angle should be equal(SAS property).
For triangles to be congruent, all the three sides and all the three angles ,ust be exactly same.
Since △ABC and △A'B'C' have only one side equal, they are neither congruent nor similar.
There is actually 3 steps:
Step 1: Adjust the bank statement balance. All your transactions for the month may not be on your bank statement. ...
Step 2: Adjust the check register balance. ...
Step 3: Compare the adjusted balances.
Hope I helped if so Mark me as brainliest
Calculus 1?
To find concavity you must take the second derivative.
As you would to find your local maximums and minimums (critical points) in the first derivative by setting y' = 0, to find points of inflection you set acceleration, y" = 0.
Now that you know where the point in which the function is neither concave up or concave down (at the points of inflection) plug x-values between them into the second derivative for x. If y" is positive between those particular points will be concave up and if y" is negative it will be concave down between that interval.
For a better understanding you might find a good video on Youtube explaining this if you search "Points of Inflections" or "Concavity of a function".
Cheers.
