4(x+3)<br> 8. =2x-3<br> X= simplify your answer

Suppose the path of a baseball follows the path graphed by the quadratic function ƒ(d) = –0.6d2 + 5.4d + 0.8 where d is the hori

GrogVix [38]

Answer:

The correct option D.

Step-by-step explanation:

The given function is

$f(d)=-0.6d^2+5.4d+0.8$

Where f(d) is the height of the ball at horizontal distance d.

Put f(d)=0, to find the distance where the ball touch the ground.

$0=-0.6d^2+5.4d+0.8$

Quadratic formula:

$d=\frac{-b\pm \sqrt{b^2-4ac}}{2a}$

Using the quadratic formula we get

$d=\frac{-5.4\pm \sqrt{(5.4)^2-4(-0.6)(0.8)}}{2(-0.6)}$

$d=-0.146,9.146$

Therefore the ball is in air between d=-0.146 to d=9.146.

The distance can not be negative, therefore the ball remains in the air between d=0 to d=9.146.

$9.146\approx 9.15$

Therefore the correct option is D.

6 0

3 years ago

Please help me!

Alex73 [517]

<h3>Answer: angle T = 70</h3>

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Work Shown:

Quadrilateral RSTU is a kite. In geometry, any kite has two pairs of adjacent congruent sides. In this case, RU = RS is one pair of adjacent congruent sides (single tickmarks), while TU = TS is the other pair of adjacent congruent sides (double tickmarks).

Draw diagonal line segment TR. This forms triangles TUR and TSR.

Through the SSS (side side side) congruence theorem, we can prove that the two triangles TUR and TSR are congruent.

Then by CPCTC (corresponding parts of congruent triangles are congruent), we can say,

angle U = angle S = 90

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Re-focus back on quadrilateral RSTU (ignore or erase line segment TR). The four angles of any quadrilateral will always add to 360 degrees. Let x be the measure of angle T.

(angleU)+(angleR)+(angleS)+(angleT) = 360

90+110+90+x = 360

290+x = 360

290+x-290 = 360-290 ... subtract 290 from both sides

x = 70

<h3>angle T = 70</h3>

4 0

3 years ago

Please help<br> A) y< 2x+4<br> B) y< 1/2x+3<br> C)y> 1/2x+3<br> D) y> 2x+3

lesya692 [45]

Answer:

B