A penny is 0.061 inch thick. What is the value of the six in the thickness of a penny
1 answer:
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Answer:
k=-9
Step-by-step explanation:
The given functions are
and
We want to find the value of k, for which
This means we need to extract g(x) from f(x) to get:
Or
Therefore k=-9
Recall that the domain of a function is the set of all x values of the function for which the function is defined.
Given that
and 
Given that
For the function to be undefined, the denominator should be zero
i.e. 2x = 0 which means that x = 0
Thus, the domain of the function is all real values of x except 0.
Therefore, the restriction is x ≠ 0.
Given that
For the function to be undefined, the denominator should be zero
i.e.
For x = 2,
Also, for x = 1
Thus, the domain of the function is all real values of x except 1 and 2.
Therefore, the restriction is x ≠ 1, 2.
Given that
For the function to be undefined, the denominator should be zero
i.e.
For x = -2,
.
Thus, the domain of the function is all real values of x except -2.
Therefore, the restriction is x ≠ -2.
Given that
There is no value of x, for which the function is undefined.
Thus, the domain of the function is all real values of x.
Therefore, there is no restrictions to the domain of the function.
Given that
For the function to be undefined, the denominator should be zero
i.e.
Thus, the domain of the function is all real values of x except -1.
Therefore, the restriction is x ≠ -1.
Given that
Given that
For the function to be undefined, the denominator should be zero
i.e. 2x = 0 which means that x = 0
Thus, the domain of the function is all real values of x except 0.
Therefore, the restriction is x ≠ 0.
Given that
For the function to be undefined, the denominator should be zero
i.e.
For x = 2,
Also, for x = 1
Thus, the domain of the function is all real values of x except 1 and 2.
Therefore, the restriction is x ≠ 1, 2.
Given that
For the function to be undefined, the denominator should be zero
i.e.
For x = -2,
Thus, the domain of the function is all real values of x except -2.
Therefore, the restriction is x ≠ -2.
Given that
There is no value of x, for which the function is undefined.
Thus, the domain of the function is all real values of x.
Therefore, there is no restrictions to the domain of the function.
Given that
For the function to be undefined, the denominator should be zero
i.e.
Thus, the domain of the function is all real values of x except -1.
Therefore, the restriction is x ≠ -1.