Answer:
105
Step-by-step explanation:
Complete Question:
<em>"Ejay bought a pack of peanut bars from the neighborhood store. He ate 1/3 of the context immediately. He gave 20 pieces to his sister Aileen. Then he ate 1/2 of the remaining bars. If he has 25 peanut bars left after, how many bars did the pack originally contain?"</em>
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Let original amount be x
He ate 1/3 immediately so remaining
x - 1/3x
He gave 20 to Aileen, remaining:
(x - 1/3x) - 20
He ate half of remaining, remaining now:
(x - 1/3x) - 20 - 1/2((x - 1/3x) - 20)
Now, he has 25 left. So the previous equation is equal to 25. Then we solve for x:
![(x - \frac{1}{3}x) - 20 - \frac{1}{2}[(x - \frac{1}{3}x) - 20)]=25\\\frac{2}{3}x-20-\frac{1}{2}[\frac{2}{3}x-20]=25\\\frac{2}{3}x-20-\frac{1}{3}x+10=25\\\frac{1}{3}x=35\\x=\frac{35}{\frac{1}{3}}\\x=105](https://tex.z-dn.net/?f=%28x%20-%20%5Cfrac%7B1%7D%7B3%7Dx%29%20-%2020%20-%20%5Cfrac%7B1%7D%7B2%7D%5B%28x%20-%20%5Cfrac%7B1%7D%7B3%7Dx%29%20-%2020%29%5D%3D25%5C%5C%5Cfrac%7B2%7D%7B3%7Dx-20-%5Cfrac%7B1%7D%7B2%7D%5B%5Cfrac%7B2%7D%7B3%7Dx-20%5D%3D25%5C%5C%5Cfrac%7B2%7D%7B3%7Dx-20-%5Cfrac%7B1%7D%7B3%7Dx%2B10%3D25%5C%5C%5Cfrac%7B1%7D%7B3%7Dx%3D35%5C%5Cx%3D%5Cfrac%7B35%7D%7B%5Cfrac%7B1%7D%7B3%7D%7D%5C%5Cx%3D105)
The pack originally had 105 bars