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Gnoma [55]
3 years ago
6

PLEASE HELP ME SOLVE THIS THANK U!!

Mathematics
1 answer:
V125BC [204]3 years ago
5 0
Step 1) Draw a dashed line through the points (0,6) and (4,7). These two points are on the line y = (1/4)x+6. To find those points, you plug in x = 0 to get y = 6. Similarly, plug in x = 4 to get y = 7. The dashed line indicates that none of the points on this line are part of the solution set.

Step 2) Draw a dashed line through (0,-1) and (1,1). These two points are on the line y = 2x-1. They are found in a similar fashion as done in step 1. 

Step 3) Shade the region that is above both dashed lines. We shade above because of the "greater than" sign. This is shown in the attached image I am providing below. The red shaded region represents all of the possible points that are the solution set. Once again, any point on the dashed line is not in the solution set. 

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Step-by-step explanation:

8 0
3 years ago
Evaluate 8a+3b-10+c^28a+3b−10+c ​2 ​​ 8, a, plus, 3, b, minus, 10, plus, c, start superscript, 2, end superscript when a=2a=2a,
ohaa [14]

Answer:

The given expression  8a+3b-10+c^2 at a = 2 , b = 5 and c = 4  is 37.

Step-by-step explanation:

Given : expression 8a+3b-10+c^2

We have to evaluate the given expression  8a+3b-10+c^2 at a = 2 , b = 5 and c = 4

Consider the given expression  8a+3b-10+c^2

Substitute, a = 2 , b= 5 and c = 4

We have,

=8(2)+3(5)-10+(4)^2

Simplify, we have,

=16+13-10+16

We get,

= 37

So,  The given expression  a+3b-10+c^2 at a = 2 , b = 5 and c = 4  is 37.

4 0
3 years ago
The length of a rectangle is 12 in. and the perimeter is
sveticcg [70]
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Hope this helped ;)
5 0
3 years ago
Read 2 more answers
Michael breeds chickens and ducks.
hodyreva [135]
Let c=cost of chicken and d=cost of duck; 50c+30d=550 and 44c+36d=532.
So 5c+3d=55, 11c+9d=133.
Therefore 15c+9d=165, subtracting 11c+9d=133 we get: 4c=32 so c=8.
5c+3d=40+3d=55, so 3d=15 and d=5.
Cost of chicken is $8 and cost of duck is $5.
4 0
3 years ago
Read 2 more answers
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