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Tpy6a [65]
3 years ago
13

Which inequality is equivalent to this one?Y-8≤-2​

Mathematics
1 answer:
Arlecino [84]3 years ago
6 0

Answer:

y-8+8

Step-by-step explanation:

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A<br> 100 cm²<br> b<br> 9 cm²<br> c<br> 225 cm²<br> d<br> 28.26 cm²
nasty-shy [4]

Answer:

28.26 cm^2

Step-by-step explanation:

A = (pi)r^2

A = 3.14 * (3 cm)^2

A = 3.14 * 9 cm^2

A = 28.26 cm^2

6 0
3 years ago
Pls help it’s very very due soon! I will mark brainlist, rate 5 stars, give you ~30 points, and thank.
Zanzabum

Answer:

answer 8 weeks

Step-by-step explanation:

7 0
3 years ago
Find the value of the expression 4a4 − 2b2 + 40 when a = 2 and b = 7.
Makovka662 [10]
4 a⁴ - 2 b² + 40 :

4 * ( 2⁴) - 2  * ( 7²)  + 40 = 

4 * 16 - 2 * 49 + 40 =

64 - 98 + 40 =

-34 + 40 =

+ 6

<span>hope this helps!</span>
4 0
3 years ago
Amber had 6 cousins. Her friend Ashley has 2 fewer than 3 times as many cousins as Amber has. Which expression represents the nu
Olin [163]

Answer:

Cousins Amber has: 6

(Let no. of cousins Amber has be represented as x)

Cousins Ashley has: 3x - 2

(3 X 6)- 2

18-2

16

8 0
3 years ago
Calc 3 iiiiiiiiiiiiiiiiiiiiiiiiiiii
Lilit [14]

Take the Laplace transform of both sides:

L[y'' - 4y' + 8y] = L[δ(t - 1)]

I'll denote the Laplace transform of y = y(t) by Y = Y(s). Solve for Y :

(s²Y - s y(0) - y'(0)) - 4 (sY - y(0)) + 8Y = exp(-s) L[δ(t)]

s²Y - 4sY + 8Y = exp(-s)

(s² - 4s + 8) Y = exp(-s)

Y = exp(-s) / (s² - 4s + 8)

and complete the square in the denominator,

Y = exp(-s) / ((s - 2)^2 + 4)

Recall that

L⁻¹[F(s - c)] = exp(ct) f(t)

In order to apply this property, we multiply Y by exp(2)/exp(2), so that

Y = exp(-2) • exp(-s) exp(2) / ((s - 2)² + 4)

Y = exp(-2) • exp(-s + 2) / ((s - 2)² + 4)

Y = exp(-2) • exp(-(s - 2)) / ((s - 2)² + 4)

Then taking the inverse transform, we have

L⁻¹[Y] = exp(-2) L⁻¹[exp(-(s - 2)) / ((s - 2)² + 4)]

L⁻¹[Y] = exp(-2) exp(2t) L⁻¹[exp(-s) / (s² + 4)]

L⁻¹[Y] = exp(2t - 2) L⁻¹[exp(-s) / (s² + 4)]

Next, we recall another property,

L⁻¹[exp(-cs) F(s)] = u(t - c) f(t - c)

where F is the Laplace transform of f, and u(t) is the unit step function

u(t) = \begin{cases}1 & \text{if }t \ge 0 \\ 0 & \text{if }t < 0\end{cases}

To apply this property, we first identify c = 1 and F(s) = 1/(s² + 4), whose inverse transform is

L⁻¹[F(s)] = 1/2 L⁻¹[2/(s² + 2²)] = 1/2 sin(2t)

Then we find

L⁻¹[Y] = exp(2t - 2) u(t - 1) • 1/2 sin(2 (t - 1))

and so we end up with

y = 1/2 exp(2t - 2) u(t - 1) sin(2t - 2)

7 0
2 years ago
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