is the length both sides already or just on one side?
because if the 16ft. is only on one side, and the sum of the both sides are 32ft, i think the width of the rectangle must be 16ft, which means 8ft from the first side and 8ft from the second side.
but if the 16ft. is the sum of both sides, which means 8ft from the first length and 8ft from the second length, then the answer for the width is 16ft, for each side of the width. 16 for the first width, and 16 for the second width.
is my explanation too complicated?? sorry hehe.
Answer:
The approximated length of the cables that stretch between the tops of the two towers is 1245.25 meters.
Step-by-step explanation:
The equation of the parabola is:

Compute the first order derivative of <em>y</em> as follows:

![\frac{\text{d}y}{\text{dx}}=\frac{\text{d}}{\text{dx}}[0.00035x^{2}]](https://tex.z-dn.net/?f=%5Cfrac%7B%5Ctext%7Bd%7Dy%7D%7B%5Ctext%7Bdx%7D%7D%3D%5Cfrac%7B%5Ctext%7Bd%7D%7D%7B%5Ctext%7Bdx%7D%7D%5B0.00035x%5E%7B2%7D%5D)

Now, it is provided that |<em>x </em>| ≤ 605.
⇒ -605 ≤ <em>x</em> ≤ 605
Compute the arc length as follows:


Now, let



Plug in the solved integrals in Arc Length and solve as follows:


Thus, the approximated length of the cables that stretch between the tops of the two towers is 1245.25 meters.
I believe it is 8x.
Use the formula A=1/2(b*h)
A=1/2(4x(5x-1))
A=1/2(20x-4x)
A=1/2(16x)
A=8x
Answer:
Step-by-step explanation: It’s the perimeter of each shape so you add the outside of the shape up. The second question is 11.2 and 12 as the width and length. The 11.2 is the width so on the other side it is 11.2, and the length is 12 so the other side is 12. You then add them all up and get your answer.
Answer:
Swimming one time around the pool is 56.5 ft
Step-by-step explanation:
Swimming 18 ft from one side of her circular pool to the other, swimming straight through the center means the circular swimming pool has a diameter of d=18 ft.
The circumference of the circle is calculated using:

where d=18 is the diameter and π=3.14 as given.
We substitute the values to get:


We approximate to the nearest tenth to get:
