Answer:
The possible values of the number of dollars in the original pile of money is ≥ $200 but < $350
Step-by-step explanation:
Here we have, pile of money ≥ $200
Amount in put the left pocket = $50
Fraction given away = 2/3 of rest of pile ≥ 2/3×150 ≥ $100
Amount put in right pocket = ≥ $150 - $100 ≥ $50
Total amount remaining with Jeri = $50 +≥ $50 ≥ $100
Also original pile - $200 < $100
Therefore where maximum amount given away to have more money = $200 we have
2/3× (original pile - 50) = $200
Maximum amount for original pile = $350
Therefore the possible values of the number of dollars in the original pile of money is ≥ $200 but < $350.
The rate would be 40 questions per hour
Sorry cant help you, that's a tough nut to crack! good luck though!
Answer: ok bet
Step-by-step explanation: theres a picture below and to graph it you simply start with the y coordinate, which is 7. you put 7 on the graph then go down 3 because 3 is negative, then go right one because 1 is postitive. (you get 1 from making the slope into a fraction, -3/1) also remember the formula for this is y=mx+b. its tricky but i hope this helped
Don’t know if there’s much of an equation for it, but I guess the best way to write it out is 10 + x = -18. Then, you would subtract the 10 from both sides in order to isolate the x. So then you’re left with x = -28. So -28 is your answer.
