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3 years ago

In Quadrilateral ABCD , AB ∥ CD, and m∠2=35°.

Mathematics

2 answers:

Marianna [84]3 years ago

4 0

Angle 2 and 5 are alternate interior angle and they are congruent. That means that m <5= 35°.

scZoUnD [109]3 years ago

4 0

we know that

Alternate interior angles are two interior angles which lie on different parallel lines and on opposite sides of a transversal. Alternate interior angles are congruent

In this problem

the parallel lines are AB and CD

the transversal line is BD

then

m∠5=m∠2 ------> by alternate interior angles

m∠5= $35\°$

therefore

the answer is

m∠5= $35\°$

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Answer:

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Step-by-step explanation:

The complete question is

The altitude of an object, d, can be modeled using the equation below:

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Let

d ----> the altitude of an object in feet

t ---> the time in seconds

v ---> initial velocity in ft per second

h ---> initial height of an object in feet

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we have

$v=90\ ft/sec$

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substitute the values and solve for t

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$-16t^2+90t+486=0$

Multiply by -1 both sides

$16t^2-90t-486=0$

The formula to solve a quadratic equation of the form $ax^{2} +bx+c=0$ is equal to

$x=\frac{-b(+/-)\sqrt{b^{2}-4ac}} {2a}$

in this problem we have

$a=16\\b=-90\\c=-486$

substitute in the formula

$t=\frac{90(+/-)\sqrt{-90^{2}-4(16)(-486)}}{2(16)}$

$t=\frac{90(+/-)\sqrt{39,204}}{32}$

$t=\frac{90(+/-)198}{32}$

$t_1=\frac{90(+)198}{32}=9\ sec$

$t_2=\frac{90(-)198}{32}=-3.375\ sec$

the solution is t=9 sec

see the attached figure to better understand the problem

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