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SashulF [63]
3 years ago
6

One sixth of students at a local college are seniors. The number of freshmen students is 2 1/2 times that amount. What fraction

of the students are freshmen?
Mathematics
2 answers:
vladimir1956 [14]3 years ago
4 0
5/12 because 1/6 equals 2/12. 2 1/2 times 2/12 equals 5/12
Rama09 [41]3 years ago
4 0

Answer: Our required fraction is \dfraac{5}{12}

Step-by-step explanation:

Since we have given that

Fraction of students at a local college = \dfrac{1}{6}

According to question,  The number of freshmen students is 2\dfrac{1}{2}=\dfrac{5}{2} times that amount.

So, Fraction of students are freshmen is given by

\dfrac{5}{2}\times \dfrac{1}{6}\\\\=\dfrac{5}{12}

Hence, our required fraction is \dfraac{5}{12}

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Shkiper50 [21]
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2 years ago
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Number of whole numbers between 45 and 69 is _________ .<br> (a) 31 (b) 23 (c) 25 (d) 28
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The number of whole number is 23 through subtracting the numbers. hope it helps ☺️

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3 years ago
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Make n the subject of the formula: M=3n
natta225 [31]
Divide each side by 3. ----- n=M/3 .
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3 years ago
RSM wants to send four of its 18 Math Challenge teachers to a conference. How many combinations of four teachers include exactly
tatiyna

Answer:

1120 combinations of four teachers include exactly one of either Mrs. Vera or Mr. Jan.

Step-by-step explanation:

The order in which the teachers are chosen is not important, which means that the combinations formula is used to solve this question.

Combinations formula:

C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

In this question:

1 from a set of 2(Either Mrs. Vera or Mr. Jan).

3 from a set of 18 - 2 = 16. So

C_{2,1}C_{16,3} = \frac{2!}{1!1!} \times \frac{16!}{3!13!} = 1120

1120 combinations of four teachers include exactly one of either Mrs. Vera or Mr. Jan.

4 0
3 years ago
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siniylev [52]
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