Question

The base of a triangle is 8 1 3 meters and the height of the triangle is the fourth root of 16 meters meters. What is the area of the triangle?

Answer 1

Answer:

The area of triangle is $8 \frac{1}{3}\ m^{2}$

Step-by-step explanation:

we know that

The area of a triangle is equal to

A=(1/2)bh

we have

b=8 1/3 m

convert to an improper fraction

8 1/3 m=(8*3+1)/3=25/3 m

The fourth root of 16 is equal to 2

$\sqrt[4]{16}=(2^{4})^{1/4}=2$

so

h=2 m

substitute

$A=(1/2)(25/3)2=25/3\ m^{2}$

convert to mixed number

$25/3=(24/3)+(1/3)=8+1/3=8 \frac{1}{3}\ m^{2}$