3 years ago

LOOK A PICTURE HURRY PLS LIKE RIGHT NOW

1 answer:

7 0

Answeri think it’s 96 or 84 I’m. It sure I had this like 3 years ago

Step-by-step explanation:

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Step-by-step explanation:

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Galina-37 [17]

M=ch x 4 next 3 = mch (34)

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3 years ago

s2008m [1.1K]

Answer:

1/a²⁷

Step-by-step explanation:

Given: $\frac{((a^2)^{-2})^5}{a^4.a^3}$

We know that when the bases are same the powers can be added. i.,e.,

(xᵃ)ᵇ = x ⁽ᵃ ⁺ ᵇ⁾

⇒ $\frac{((a^2)^{-2})^5}{a^4.a^3} \implies \frac{(a^2)^{-10}}{a^7}$

$\implies \frac{a^{-20}}{a^7} = a^{-20 - 7} = a^{-27}$

Also, $\frac{x^a}{x^b} = x^{a - b}$

This is nothing but, $\frac{1}{a^{27}}$ .

Note that $a$ cannot be zero here. The condition is provided in the question as well.

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steposvetlana [31]

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4 years ago

o-na [289]

Answer:

To complete the square the equation would be 2(x+4)^2-29

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3 years ago