There are 2 roots so the only way to complete the square is,
![y=2x^2+8x-9\\y=2[(x^2+4x)]-9\\y=2[(x^2+4x+4)-4]-9\\y=2[(x+2)^2-4]-9\\y=2(x+2)^2-8-9\\y=2(x+2)^2-17](https://tex.z-dn.net/?f=y%3D2x%5E2%2B8x-9%5C%5Cy%3D2%5B%28x%5E2%2B4x%29%5D-9%5C%5Cy%3D2%5B%28x%5E2%2B4x%2B4%29-4%5D-9%5C%5Cy%3D2%5B%28x%2B2%29%5E2-4%5D-9%5C%5Cy%3D2%28x%2B2%29%5E2-8-9%5C%5Cy%3D2%28x%2B2%29%5E2-17)
Just factor 2 out of 2x^2+8x (just ignore the -9) then find the number that will make the terms be able to complete the square.
then complete the square and multiply 2 inside the brackets.
subtraction as you already get the vertex form and know how to complete the square.
Vertex Form: 
Answer:
1/3
Step-by-step explanation:
reduce 2/6 by dividing by 2
12
x 10
______
120
it's pretty simply,sorry if I got it wrong,i'm kinda tired<span />
Yes, It is reasonable. I think this because you are dealing with 60 blocks, and out of every 5 blocks there are 3 red. 5 goes into 60 12 times. 3 multiplied by 12 is 36. 36 is more than 32. So, I think that it is reasonable. If this explanation didn't make sense, then feel free to ask for more. I hope this helped!
Answer:
across
3. 6x
4. 14mn
5. 31
6. 25b
9. 5abc
down
1. 3y
4. 19m
5. 3m2np2
7. 7y
8. 9x
Step-by-step explanation:
hope this helps
