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Nady [450]
3 years ago
13

PLEASE HELP DUE IN LESS THAN 10 MINUTES. Thank you

Mathematics
1 answer:
Mrac [35]3 years ago
6 0

Answer:

answer is B all the best for your exam

Step-by-step explanation:

please follow me

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Someone please answer these
Ede4ka [16]

Answer:

JJKJHJKHKJHKJH

Step-by-step explanation:

3 0
3 years ago
Solve the following equation for d:<br> D<br> — =7<br> 5
SIZIF [17.4K]

Answer: x = 35

Explanation: In this problem, notice that D is being divided by 5,

so to get D by itself, we need to multiply both sides of the equation by 5.

Notice that on the left side, the 5 and 5 cancel

each other out, so we are just left with D.

On the right side, we have (7)(5) which is 35.

So x = 35.

Finally, remember that we can check our answer

by plugging a 35 back into the original equation.

So we have \frac{(35)}{5} = 7.

Since this is a true statement, we know that our answer is correct, x = 35.

6 0
3 years ago
Please help me with this question!
alisha [4.7K]

Answer:

i think H(5) plus the 50 $ but it may be wrong

Step-by-step explanation:

If H is 60 then 5 times is 300 plus the 50 he already had so it all adds up to 350

8 0
3 years ago
Describe the transformation in the figure below
Keith_Richards [23]

Answer:

A) Reflection.

Step-by-step explanation:

From the figure shown, we can see that the blue triangle is flipped about the x-axis to form the red triangle.

When an object is flipped about a line, then this transformation is called reflection about that line.

Thus, we can say that reflection is taking place in the figure shown in which the x-axis is acting like a mirror. The blue triangle is the pre-image and the red triangle is the image after reflection.

The reflection about x-axis is given by:

Pre-image(x,y)\rightarrow Image(x,-y)

We can check the co-ordinates of the triangles and confirm the the transformation occurring

Points of pre-image triangle:

(0,2),(4,5),(6,2)

Points of image triangle

(0,-2),(4,-5),(6,-2)

Thus, the transformation is reflection.

3 0
3 years ago
The y coordinate of the vertex of f (x)=-x^2+8x+7 is f(4)
azamat

Hello there.

To answer this question, we need to remember some properties about the vertex of quadratic functions.

Let f(x)=ax^2+bx+c,~a\neq0. Its vertex can be found on the coordinates (x_v,~y_v) such that x_v=-\dfrac{b}{2a} and y_v=-\dfrac{b^2}{4a}+c, in which y_v=f(x_v).

Using the coefficients given by the question, we get that:

x_v=-\dfrac{8}{2\cdot(-1)}\\\\\\ x_v=-\dfrac{8}{-2}\\\\\\ x_v=4

Thus, we have:

y=f(x_v)=f(4)

So the statement is true, because the x coordinate of the vertex of the function is equal to 4.~~\checkmark

7 0
2 years ago
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