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Alex787 [66]
3 years ago
14

Four pounds of apples cost $5. Eight pounds of apples cost $10. If the total cost of apples, y, varies directly with the number

of pounds of apples purchased, x, what is the cost of 6 pounds of apples? Round your answer to the nearest hundredth.
Mathematics
2 answers:
VikaD [51]3 years ago
4 0
5/4 = 1.25 per lb

1.25 * 6 = $ 7.50 <==
antoniya [11.8K]3 years ago
3 0

Answer:

The cost of the 6 pounds of apples is $7.5 .

Step-by-step explanation:

As y = Total cost of the apple.

    x =  The number of pounds of apples purchased .

As given

If the total cost of apples, y, varies directly with the number of pounds of apples purchased, x.

i.e

y \propto x

y = kx

Where k is the constant of proportionality .

As given

Four pounds of apples cost $5.

x = 4 , y = 5

Put in y = kx

5 = 4k

k = \frac{5}{4}

k = 1.25

Eight pounds of apples cost $10.

x = 8 , y = 10

Put in y = kx

10 = 8k

k = \frac{10}{8}

k = 1.25

Now find out the cost of 6 pounds of apples.

x = 6 and k = 1.25

Put in the y = kx

y = 6 × 1.25

y = $7.5

Therefore the cost of the 6 pounds of apples is $7.5 .



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svlad2 [7]

Answer:

Step-by-step explanation:

so we are looking for the x intercept (where the line crosses the x axis).

to do this, we sub in 0 for y and solve for x.

y = 1/2x + 4....sub in 0 for y

0 = 1/2x + 4

-1/2x = 4

x = 4 * -2

x = -8 <=== so it crosses the x axis at (-8,0)

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Step-by-step explanation:

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Men are believed to have a slightly longer average length of short hospital stays than women; 5.2 days versus 4.5 days respectiv
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Answer:

Since our calculated value is lower than our critical value,z_{calc}=2.02, we have enough evidence to FAIL to reject the null hypothesis at 1% of singificance. So there is not nough evidence to conclude that mean for men it's significantly higher than the mean for female.

Step-by-step explanation:

1) Data given and notation  

\bar X_{1}=5.2 represent the mean for group men  

\bar X_{2}=4.5 represent the mean for group women  

Assuming these values for the remaining data:

\sigma_{1}=1.2 represent the population standard deviation for the sample men

\sigma_{2}=1.5 represent the population standard deviation for the sample women

n_{1}=32 sample size for the group men  

n_{2}=30 sample size for the group women  

z would represent the statistic (variable of interest)

p_v represent the p value  

2) Concepts and formulas to use  

We need to conduct a hypothesis in order to check if the mean for men it's higher than the mean for women, the system of hypothesis would be:  

H0:\mu_{1} \leq \mu_{2}  

H1:\mu_{1} > \mu_{2}  

If we analyze the size for the samples both are higher than 30, and we know the population deviation's, so for this case is better apply a z test to compare means, and the statistic is given by:  

z=\frac{\bar X_{1}-\bar X_{2}}{\sqrt{\frac{\sigma^2_{1}}{n_{1}}+\frac{\sigma^2_{2}}{n_{2}}}} (1)  

z-test: Is used to compare group means. Is one of the most common tests and is used to determine whether the means of two groups are equal to each other.  

3) Calculate the statistic  

We have all in order to replace in formula (1) like this:  

z=\frac{5.2-4.5}{\sqrt{\frac{1.2^2}{32}+\frac{1.5^2}{30}}}=2.02  

4) Find the critical value

In order to find the critical value we need to take in count that we are conducting a right tailed test, so we are looking on the normal standard distribution a value that accumulats 0.01 of the area on the right and 0.99 of the area on the left. We can us excel or a table to find it, for example the code in Excel is:

"=NORM.INV(1-0.01,0,1)", and we got z_{critical}=2.33

5) Statistical decision

Since our calculated value is lower than our critical value,z_{calc}=2.02, we have enough evidence to FAIL to reject the null hypothesis at 1% of significance. So there is not nough evidence to conclude that mean for men it's significantly higher than the mean for female.

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elena-14-01-66 [18.8K]

Answer: No

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Answer:

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