What is the Zero of f ?

rosijanka [135]

Answer:

12. -11

13. 2

Step-by-step explanation:

12. First recall the order of operations (BEDMAS): Brackets, Exponents, Division, Multiplication, Addition, Subtraction

For question 12 there is a division and its priority is before other operations in the equation so you must divide 16/-2 first which gives you -8.

From there because addition and subtraction is on the same level of order, you would do the question straight as it is shown (but replace 16/-2 with -8.

Your new equation is -10-8+7 = -11

13. follow the same as above using BEDMAS. It may help to look at it with additional brackets: ((-68)/(-4)) + ((5 x (-3))

keep in mind there’s an addition between the two

Division and multiplication is on the same level in BEDMAS so first divide -68/-4 = 17

Second multiply 5 x -3 = -15

Now you can combine the two answers using addition: 17 + (-15) = 2

5 0

2 years ago

Write the slope-intercept form of the equation of the line described.

Ad libitum [116K]

7)

Given the line

$y=-x+2$

We know that the slope-intercept form of the line equation is

$y=mx+b$

here

m is the slope and b is the intercept

Thus, the slope = -1

We know that the parallel lines have the same. Thus, the slope of the parallel line is: -1

Using point-slope of the line equation

$y-y_1=m\left(x-x_1\right)$

substituting the values m = -1 and the point (4, 0)

$y-0 = -1 (x-4)$

Writing in the slope-intercept form

$y = -x+4$

Thus, the slope-intercept form of the equation of the line equation parallel to y=-x+ 2 will be:

$y = -x+4$

8)

Note: Your line is a little bit unclear. But, I am assuming the

ine is: y = -x-1

Given the assumed line

y = -x-1

We know that the slope-intercept form of the line equation is

$y=mx+b$

here

m is the slope and b is the intercept

Thus, the slope = m = -1

We know that a line perpendicular to another line contains a slope that is the negative reciprocal of the slope of the other line, such as:

slope = m = -1

perpendicular slope = – 1/m = -1/-1 = 1

Using point-slope of the line equation

$y-y_1=m\left(x-x_1\right)$

substituting the values m = 1 and the point (4, 3)

$y - 3 = 1 (x-4)$

Writing in the slope-intercept form

y-3 = x-4

y = x-4+3

y = x - 1

Thus, the slope-intercept form of the equation of the line equation perpendicular to y = -x-1 will be:

y = x - 1

5 0

2 years ago

Need Help Rn!!!

fgiga [73]

It would be 5850 hope you get it right:)

7 0

3 years ago

Find x when y = 32, given that x varies inversely as y, and x = 132 when y = 4.

gizmo_the_mogwai [7]

Answer:

When y=32, x=16.5

Step-by-step explanation:

Find x when y = 32, given that x varies inversely as y, and x = 132 when y = 4.

We are given:

x varies inversely with y

We can write it as: $x\:\alpha \:\frac{1}{y}$

$x=\frac{k}{y}$

We have x = 132, when y=4

We can find value of k by using these values

$x=\frac{k}{y}\\132=\frac{k}{4}\\k=132*4\\k=528$

We need to find x when y=32

$x=\frac{k}{y}\\x=\frac{528}{32}\\x=16.5$

So, when y=32, x=16.5

6 0

3 years ago

Work out the size of angle x

Ksju [112]

Answer:

35 deg

Step-by-step explanation:

since ABC is straight line. angle ABC should be 180 deg. implies

$45 + 100 + x = 180 \\ x = 180 - 100 - 45 \\ x = 35 \: degree$

6 0

2 years ago