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adell [148]
3 years ago
15

PLEASE HELP!- Find the slope of the line

Mathematics
1 answer:
AleksandrR [38]3 years ago
8 0
It is positive, so you would do rise divided by run to get the slope
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Tara has 3 over 4 cup of ice cream. How many 1 over 5 -cup servings are in 3 over 4 cup of ice cream?
qwelly [4]

Answer:

0.15 cup servings

Step-by-step explanation:

sorry if its wrong idk

8 0
3 years ago
Q#2 Graph the relation in the table.Then use the vertical-line test.Is the relation a function
tresset_1 [31]
The graph of the relation between x and y is as shown in attached figure

By applying the vertical line test we find that the relation is not a function because there are two points which are (1,-1) , (1,3) have the same value of x with different values of y which contradicts with with the rule of function.


5 0
3 years ago
Read 2 more answers
Can you help please? It would be helpful.
steposvetlana [31]

Answer:

660 square feet

Step-by-step explanation:

1 chain = 66 feet

Length ( l ) = 66 feet

Breadth ( b ) = 10 feet

To find :

The area of a cricket pitch in square feet = ?

The area of a cricket pitch in square feet will be in the shape of rectangle.

Formula : -

Area of a rectangle = lb

Area of a rectangle

= 66 x 10

= 660 square feet

Therefore,

660 square feet is the area of a cricket pitch.

8 0
3 years ago
The number of events is 29​, the number of trials is 298​, the claimed population proportion is​ 0.10, and the significance leve
Nina [5.8K]

Answer:

z=\frac{0.0973 -0.1}{\sqrt{\frac{0.1(1-0.1)}{298}}}=-0.155  

p_v =2*P(Z  

And we can use excel to find the p value like this: "=2*NORM.DIST(-0.155;0;1;TRUE)"

So the p value obtained was a very high value and using the significance level given \alpha=0.05 we have p_v>\alpha so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can said that at 5% of significance the proportion of interest is not significantly different from 0.1 .  

Step-by-step explanation:

1) Data given and notation

n=298 represent the random sample taken

X=29 represent the events claimed

\hat p=\frac{29}{298}=0.0973 estimated proportion

p_o=0.1 is the value that we want to test

\alpha=0.05 represent the significance level

Confidence=95% or 0.95

z would represent the statistic (variable of interest)

p_v represent the p value (variable of interest)  

2) Concepts and formulas to use  

We need to conduct a hypothesis in order to test the claim that the proportion is 0.1 or no.:  

Null hypothesis:p=0.1  

Alternative hypothesis:p \neq 0.1  

When we conduct a proportion test we need to use the z statistic, and the is given by:  

z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}} (1)  

The One-Sample Proportion Test is used to assess whether a population proportion \hat p is significantly different from a hypothesized value p_o.

3) Calculate the statistic  

Since we have all the info requires we can replace in formula (1) like this:  

z=\frac{0.0973 -0.1}{\sqrt{\frac{0.1(1-0.1)}{298}}}=-0.155  

4) Statistical decision  

It's important to refresh the p value method or p value approach . "This method is about determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.  

The next step would be calculate the p value for this test.  

Since is a bilateral test the p value would be:  

p_v =2*P(Z  

And we can use excel to find the p value like this: "=2*NORM.DIST(-0.155;0;1;TRUE)"

So the p value obtained was a very high value and using the significance level given \alpha=0.05 we have p_v>\alpha so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can said that at 5% of significance the proportion of interest is not significantly different from 0.1 .  

We can do the test also in R with the following code:

> prop.test(29,298,p=0.1,alternative = c("two.sided"),conf.level = 1-0.05,correct = FALSE)

7 0
3 years ago
Identify one solution for this graph
sp2606 [1]
(0,0), (1,1)
Basically, any point that is shaded.
7 0
3 years ago
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