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Sidana [21]
3 years ago
5

Identify one solution for this graph

Mathematics
1 answer:
sp2606 [1]3 years ago
7 0
(0,0), (1,1)
Basically, any point that is shaded.
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Solve −5x = 15. (1 point)<br><br><br> −3<br> 3<br> 10<br> 20
Luba_88 [7]
Remember you can do anything to an eqautoin as long as you do oit to both sides

-5x=15
try to get 1x by itself

remember
(ax)/a=x when a=a

so
-5x=15
get x
divide both sides by -5
remember to flip sign
(-5x)/(-5)=15/(-5)
x=-3

answer is first one
x=-3 

8 0
3 years ago
Read 2 more answers
Find xif S is between R and T, RS=2x+3, ST=4x, and RT=63
borishaifa [10]

Answer:

x = 10

Step-by-step explanation:

If S is between R and T, then RS + ST will be equal to RT.

See image.

Use this idea to write an equation.

2x + 3 + 4x = 63

Combine like terms, Subtract 3, Divide by 6, to solve for x. See image.

4 0
2 years ago
Let point C be between V and W on VW Given that VW = 61, VC = z + 13, and CW = z + 8, solve for z.
LenKa [72]
VW = VC + CW
61 = z + 13 + z + 8 = 2z + 21
2z = 61 - 21 = 40
z = 40/2 = 20
z = 20.
3 0
3 years ago
If 5 notebooks cost $5.25 how much is 3 notebooks
mrs_skeptik [129]
3 notebooks will cost $3.15
6 0
3 years ago
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Jaiden invests his money in an account that compounds interest annually. What can he expect to happen to the balance of his acco
Nonamiya [84]
Option B. The balance will increase more and more each year, but it will not be linear. Unlike simple interest that tends to produce linear graphs; the returns when compounded can get very astronomical. The mathematics behind compound interest is "multiplication". Your funds get multiplied, not added or decreased and this is because the previous interest is accrued on the principal and the current interest. Unlike compound interest simple interest is linear, it increases (or decreases) steadily. As time goes on with simple interest,  one's returns increases very steadily but this is unlike compound interest.  So yes,  Option B,  the balance will increase more and more each year, but it will not be linear.
7 0
4 years ago
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