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ivann1987 [24]
3 years ago
11

a ladder 13m long is placed on the ground in such a way that it touches the top of a vertical wall 12m high. find the distance o

f the foot of the ladder from the bottom of the wall​
Mathematics
1 answer:
Sergio039 [100]3 years ago
8 0

Answer:

by applying Pythagoras theorem;

the ladder(13m) acts as hypotenuse

the wall (12m) acts as height

the distance between the the two is the base

therefore

a² + b² = c²

b²= c²- a²

b²= 169 - 144

b² = 25

√b² = √25

b= 5m

the distance is 5m

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Solve: | −2n | + 10 = −50<br><br><br> (Find Solution)
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Answer:

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Step-by-step explanation:

| −2n | + 10 = −50

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Given the system of equations:
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Answer:

x=4

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Step-by-step explanation:

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2x+2y=12,2x+2(−1)y=2×2

Simplify.

2x+2y=12,2x−2y=4

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8 0
2 years ago
Read 2 more answers
A floor of a room is in the shape of square. It is to be covered with rectangular tiles that each have an area of 192 square inc
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Find area of room
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in a square, legnth=width
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convert o inches
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how many tiles will cover all of floor?
aka
how many 192 in^2 is at least 28224 (at least, because we need to cover the whole floor without gaps)
192x<u>></u>28224
divide both sides by 192
x<u>></u>147

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8 0
3 years ago
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4TH TIME ASKING THIS!!! Please help me! Someone pleaseeee. I need the correct answers. I don’t want to fail
Alexeev081 [22]

Answer:

The functions are inverses; f(g(x)) = x ⇒ answer D

h^{-1}(x)=\sqrt{\frac{x+1}{3}} ⇒ answer D

Step-by-step explanation:

* <em>Lets explain how to find the inverse of a function</em>

- Let f(x) = y

- Exchange x and y

- Solve to find the new y

- The new y = f^{-1}(x)

* <em>Lets use these steps to solve the problems</em>

∵ f(x)=\sqrt{x-3}

∵ f(x) = y

∴ y=\sqrt{x-3}

- Exchange x and y

∴ x=\sqrt{y-3}

- Square the two sides

∴ x² = y - 3

- Add 3 to both sides

∴ x² + 3 = y

- Change y by f^{-1}(x)

∴ f^{-1}(x)=x^{2}+3

∵ g(x) = x² + 3

∴ f^{-1}(x)=g(x)

∴ <u><em>The functions are inverses to each other</em></u>

* <em>Now lets find f(g(x))</em>

- To find f(g(x)) substitute x in f(x) by g(x)

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∴ ± \sqrt{\frac{x+1}{3}}=y

∵ x ≥ 0

∴ We will chose the positive value of the square root

∴ \sqrt{\frac{x+1}{3}}=y

- replace y by h^{-1}(x)

∴ h^{-1}(x)=\sqrt{\frac{x+1}{3}}

4 0
3 years ago
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