Permutation: In a race of 10 students, find the number of ways students can finish 1st, 2nd, and 3rd. In this case the order matters, so it is a permutation.
10 x 9 x 8 = 720 ways
Combination: In a class of 10 students, find the number of ways a group of 3 students can be selected to win a prize. In this case the order doesn't matter, so it's a combination.
10 x 9 x 8 / (3 x 2 x 1) = 120 ways
143 x 2 = 286 because if you mulitpy each by 2 you get 286
Answer:
Step-by-step explanation:
The real part does not have i as a multiplier. It is 23.3.
The imaginary part* is the coefficient of i: 44.
_____
* There is some disagreement as to whether the imaginary part includes i or not. One source says the imaginary part is the part that has i as a factor (44i). Another source says the imaginary part is the real number that multiplies i (44). Above, we have used the latter definition. Please consult your curriculum materials for the definition you should use.
The answer is-. 63
.0= tenths
.00= hundredths
how to round:
ex. let's say the number is 51 and it says to round to the nearest tens place you look at the new mber before it to round. So you would loom at the 1, keep in mind that any number lower than 5 toy round down. so the answer would be 50. Now consider the number 57 you would round up because 5 or greater you would round up so it would be 60.
