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Iteru [2.4K]
3 years ago
12

Translate the following phrase to a mathematical expression: a number times fifteen.

Mathematics
2 answers:
crimeas [40]3 years ago
8 0

Answer:

it could either be n15

15n

because a number multiplied by 5 is

n15

but in mathematics a number comes before a letter when writing a mathematical expression

andre [41]3 years ago
8 0

Answer:

The answer is n15

Hope this helps!!!

Please mark as brainliest

Step-by-step explanation:

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3 years ago
Solve for and in the following simultaneous equations below; 5x−4y=8 and 2x+y=11.
lorasvet [3.4K]

Answer:

x=4 and y=3

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7 0
3 years ago
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The sum of two numbers is 53 and the difference is 11. What are the numbers ?
eimsori [14]
The numbers are 32 and 21
32 + 21 = 53
32 - 21 = 11
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3 years ago
Ms. De Leon wants to produce different sets of test questions for her essay test. If she plans to do this by putting together 3
gladu [14]
The correct answer is b
5 0
3 years ago
What are the solutions of the equation x6 + 6x3 + 5 = 0? Use factoring to solve. mc017-1.jpg and x = 1 mc017-2.jpg and x = –1 mc
Wittaler [7]

We are given equation :x^6+6x^3+5=0

Use\:the\:rational\:root\:theorem

\mathrm{Therefore,\:we\:need\:to\:check\:the\:following\:rational\:numbers:\quad }\pm \frac{1,\:5}{1}

-\frac{1}{1}\mathrm{\:is\:a\:root\:of\:the\:expression,\:so\:factor\:out\:}x+1

\mathrm{Compute\:}\frac{x^6+6x^3+5}{x+1}\mathrm{\:to\:get\:the\:rest\:of\:the\:eqution:\quad }x^5-x^4+x^3+5x^2-5x+5

Therefore, final factored form it

x^6\:+\:6x^3\:+\:5=\left(x+1\right)\left(x^5-x^4+x^3+5x^2-5x+5\right)

We can't factor it more.

Therefore,

x+1=0.

x=-1.

Therefore, the real solution of the equation would be -1.


5 0
3 years ago
Read 2 more answers
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