Initial velocity (u) = 0m/s
Final velocity (v) = 20m/s
Time (t) = 10 s
Acceleration (a)
= (v - u)/t
= [(20m/s) - (0m/s)]/10s
= (20m/s)/10s
= (20m/s²)/10
=> 2m/s²
Answer:
The center/ mean will almost be equal, and the variability of simulation B will be higher than the variability of simulation A.
Step-by-step explanation:
Solution
Normally, a distribution sample is mostly affected by sample size.
As a rule, sampling error decreases by half by increasing the sample size four times.
In this case, B sample is 2 times higher the A sample size.
Now, the Mean sampling error is affected and is not higher for A.
But it's sample is huge for this, Thus, they are almost equal
Variability of simulation decreases with increase in number of trials. A has less variability.
With increase number of trials, variability of simulation decreases, so A has less variability.
Is it divide after the equal sign? I will text you on message. follow me
The total cost is $17,955.
Let x be the total amount of his tuition. He paid for 44% of it, or 0.44, with his scholarship. This leaves 100%-44% = 56% = 0.56 of it to be taken care of with loans. We know he took out 10054.52 in loans:
0.56x = 10054.52
Divide both sides by 0.56:
0.56x/0.56 = 10054.52/0.56
x = 17954.50 ≈ 17955
