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TEA [102]
3 years ago
8

What is the answer for this one ?

Mathematics
1 answer:
fredd [130]3 years ago
7 0

Option B:

$f^{-1}(x)=\frac{3-x}{14}

Solution:

Given function is f(x)=3-14 x.

To find the inverse of the function:

Let y = f(x)

y=3-14 x

Subtract 3 on both sides of the equation, we get

y-3=-14 x

Divide by –14 on both sides of the equation.

$\frac{y-3}{-14} =\frac{-14x}{-14}

$\frac{y-3}{-14} =x

Negative sign in the denominator go to the numerator , we get

$\frac{3-y}{14} =x

We know that y = f(x)   ⇒ x=f^{-1}(y)

Substitute x=f^{-1}(y)

$\frac{3-y}{14} =f^{-1}(y)

Since the choice of the variable is arbitrary, we can write this as

$\frac{3-x}{14} =f^{-1}(x)

$f^{-1}(x)=\frac{3-x}{14}

Hence Option B is the correct answer.

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laila [671]
Hi, this is the notation for inclusion of all real numbers.

x \in \mathbb{R}

We can also state numbers which are positive or negative with a sign on top of the R notation like so:

x \in \mathbb{R}^{+} \text{ or } x \in \mathbb{R}^{-}
7 0
3 years ago
In a certain Algebra 2 class of 30 students, 19 of them play basketball and 12 of them play baseball. There are 8 students who p
Alenkinab [10]

Answer:

Probability that a student chosen randomly from the class plays basketball or baseball is  \frac{23}{30} or 0.76

Step-by-step explanation:

Given:

Total number of students in the class = 30

Number of students who plays basket ball = 19

Number of students who plays base ball = 12

Number of students who plays base both the games = 8

To find:

Probability that a student chosen randomly from the class plays basketball or baseball=?

Solution:

P(A \cup B)=P(A)+P(B)-P(A \cap B)---------------(1)

where

P(A) = Probability of choosing  a student playing basket ball

P(B) =  Probability of choosing  a student playing base ball

P(A \cap B) =  Probability of choosing  a student playing both the games

<u>Finding  P(A)</u>

P(A) = \frac{\text { Number of students playing basket ball }}{\text{Total number of students}}

P(A) = \frac{19}{30}--------------------------(2)

<u>Finding  P(B)</u>

P(B) = \frac{\text { Number of students playing baseball }}{\text{Total number of students}}

P(B) = \frac{12}{30}---------------------------(3)

<u>Finding P(A \cap B)</u>

P(A) = \frac{\text { Number of students playing both games }}{\text{Total number of students}}

P(A) = \frac{8}{30}-----------------------------(4)

Now substituting (2), (3) , (4) in (1), we get

P(A \cup B)= \frac{19}{30} + \frac{12}{30} -\frac{8}{30}

P(A \cup B)= \frac{31}{30} -\frac{8}{30}

P(A \cup B)= \frac{23}{30}

7 0
3 years ago
X=3m/2-m <br><br>make m the subject of the formula<br>help me plss
wel

Answer:

2X/(3+X)

Step-by-step explanation:

X = 3m/2-m

Cross multiply both sides

X × (2-m)= 3m

2X-Xm= 3m

2X= 3m+Xm

2X= m(3+X)

Divide both sides by the coefficient of m which is (3+X)

m= 2X/(3+X)

8 0
3 years ago
Sorry for the black part
klemol [59]

Answer:

the second option

Step-by-step explanation:

The distance above sea

8 0
3 years ago
Find X to solve to problem and find all the angles
sesenic [268]

Answer:

Step-by-step explanation:

x + x + 65 °+ 25° = 180° ( being sum of angles of triangle )

2x + 90° = 180°

2x = 90°

x = 45

now

<A = 45°

< B = x + 65° = 45 °+ 65 °= 110°

< C = 25°

Hope it helps :)

8 0
3 years ago
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