Using the <em>normal approximation to the binomial</em>, it is found that there is a 0.0041 = 0.41% probability that at most 10 of them married their first love.
<h3>Normal Probability Distribution
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In a <em>normal distribution</em> with mean and standard deviation , the z-score of a measure X is given by:
- It measures how many standard deviations the measure is from the mean.
- After finding the z-score, we look at the z-score table and find the p-value associated with this z-score, which is the percentile of X.
- The binomial distribution is the <u>probability of x successes on n trials, with p probability of a success on each trial</u>. It can be approximated to the normal distribution with , as long as and .
In this problem:
- 40% of people marry their first love, hence .
- A sample of 50 adults is taken, hence .
For the approximation, the mean and the standard deviation are given by:
Using continuity correction, the probability that <u>at most 10</u> of them married their first love is , which is the <u>p-value of Z when X = 10.5.</u>
has a p-value of 0.0041.
0.0041 = 0.41% probability that at most 10 of them married their first love.
To learn more about the <em>normal approximation to the binomial</em>, you can take a look at brainly.com/question/14424710
What is the grid? If there is a grid I cant see it.
C. Buying it a percent discount without sales tax.
Because of not having to pay $10, so it is awesome.
slope is rise over run.
Which segments from each triangle represent rise and which represent run?
little triangle: rise is BD and run is DA
big triangle: rise is CE and run is EA
Answer: D
Formula for slope-intercept is y = mx+b. The y-intercept is the point where the line crosses the y-axis. From there on, use the slope to graph the line. For example, if the equation is y = 5x - 2, you would want to plot (0,-2) first on the graph. Then, continue using the slope, which is 5. Slope is rise/run. In this case, you go up five, then to the right one, since there is always an invisible one if the slope is a whole number.
Hope that helped. :)