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3 years ago

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the sum of the digits of a two digit number is 9. if the digits were reversed, the new number would be 9 more than the original

number. find the original number.

1 answer:

Sphinxa [80]3 years ago

3 0

18 because 8+1=9 and if you reverse it its 18 which is 9 more than 9

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How many triangles can be constructed with angles measuring 10º, 80º, and 90º?

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Olin [163]

Answer:

Step-by-step explanation:

if A = 1 2 b then it comes to h

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3 years ago

Which statement is true regarding the graphed functions? A) f(4)=g(4) B) f(4)=g(-2) C) f(2)=g(-2) D) f(-2)=g(-2)

fomenos

Answer:

Option (D)

Step-by-step explanation:

If the two points $(x_1,y_1)$ and $(x_2,y_2)$ are lying of the line.

Slope of the line represented by the function 'f' = $\frac{y_2-y_1}{x_2-x_1}$

Two points are lying on the line are (-2, 4) and (0, -2).

Slope of the line passing through these points 'm' = $\frac{4+2}{-2-0}$

m = -3

Y-intercept of the line 'b' = -2 [From the graph]

Therefore, equation of the function will be,

f(x) = (-3)x - 2

f(x) = -3x - 2

Similarly, for other function represented by the line in red,

Slope of the line passing through (-6, 0) and (0, 6) = $\frac{6-0}{0+6}$

m' = 1

Y-intercept of g(x) = 5 [From the graph]

Equation that represents the function g(x) = 1.x + 5

g(x) = x + 5

For g(x) = f(x)

-3x - 2 = x + 6

-3x - x = 2 + 6

-4x = 8

x = -2

Therefore, for x = -2 both the functions will have the value.

f(-2) = g(-2)

Option (D) will be the answer.

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3 years ago

Show work please<br> \sqrt(x+12)-\sqrt(2x+1)=1

Nesterboy [21]

Answer:

$x=4$

Step-by-step explanation:

Given $\displaystyle\\\sqrt{x+12}-\sqrt{2x+1}=1$ , start by squaring both sides to work towards isolating $x$ :

$\displaystyle\\\left(\sqrt{x+12}-\sqrt{2x+1}\right)^2=\left(1\right)^2$

Recall $(a-b)^2=a^2-2ab+b^2$ and $\sqrt{a}\cdot \sqrt{b}=\sqrt{a\cdot b}$ :

$\displaystyle\\\left(\sqrt{x+12}-\sqrt{2x+1}\right)^2=\left(1\right)^2\\\implies x+12-2\sqrt{(x+12)(2x+1)}+2x+1=1$

Isolate the radical:

$\displaystyle\\x+12-2\sqrt{(x+12)(2x+1)}+2x+1=1\\\implies -2\sqrt{(x+12)(2x+1)}=-3x-12\\\implies \sqrt{(x+12)(2x+1)}=\frac{-3x-12}{-2}$

Square both sides:

$\displaystyle\\(x+12)(2x+1)=\left(\frac{-3x-12}{-2}\right)^2$

Expand using FOIL and $(a+b)^2=a^2+2ab+b^2$ :

$\displaystyle\\2x^2+25x+12=\frac{9}{4}x^2+18x+36$

Move everything to one side to get a quadratic:

$\displaystyle-\frac{1}{4}x^2+7x-24=0$

Solving using the quadratic formula:

A quadratic in $ax^2+bx+c$ has real solutions $\displaystyle x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}$ . In $\displaystyle-\frac{1}{4}x^2+7x-24$ , assign values:

$\displaystyle \\a=-\frac{1}{4}\\b=7\\c=-24$

Solving yields:

$\displaystyle\\x=\frac{-7\pm \sqrt{7^2-4\left(-\frac{1}{4}\right)\left(-24\right)}}{2\left(-\frac{1}{4}\right)}\\\\x=\frac{-7\pm \sqrt{25}}{-\frac{1}{2}}\\\\\begin{cases}x=\frac{-7+5}{-0.5}=\frac{-2}{-0.5}=\boxed{4}\\x=\frac{-7-5}{-0.5}=\frac{-12}{-0.5}=24 \:(\text{Extraneous})\end{cases}$

Only $x=4$ works when plugged in the original equation. Therefore, $x=24$ is extraneous and the only solution is $\boxed{x=4}$

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2 years ago