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11Alexandr11 [23.1K]
3 years ago
5

X=3m/2-m make m the subject of the formulahelp me plss

Mathematics
1 answer:
wel3 years ago
8 0

Answer:

2X/(3+X)

Step-by-step explanation:

X = 3m/2-m

Cross multiply both sides

X × (2-m)= 3m

2X-Xm= 3m

2X= 3m+Xm

2X= m(3+X)

Divide both sides by the coefficient of m which is (3+X)

m= 2X/(3+X)

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Help needed bad at math
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first and second part put 0.75, then multiply 0.75 by 2 to get 1.50, then write in the third part 1 and 1/2

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Which term of the Ap: 3,8,13,18.......is 78?<br>​
Alex Ar [27]

Answer:

             \bold{a_{16}=78}

Step-by-step explanation:

a_1=3,\ a_2=3+5=8,\ a_3=8+5=13,\ a_4=13+5=18\ \implies\ d=5\\\\a_n=a_1+(n-1)d\\\\a_n=3+(n-1)(5)\\\\a_n=3+5n-5\\\\a_n=5n-2\\\\ a_n=78\quad\implies\quad n=\,??\\\\78=5n-2\\\\78+2=5n\\\\5n=80\\\\n=16

4 0
3 years ago
Prove divisibility 45^45·15^15 by 75^30
Anuta_ua [19.1K]

Answer:

3^{75}

Step-by-step explanation:

We are asked to divide our given fraction: \frac{45^{45}*15^{15}}{75^{30}}.

We will simplify our division problem using rules of exponents.

Using product rule of exponents (a*b)^n=a^n*b^n we can write:

45^{45}=(3*15)^{45}=3^{45}*15^{45}

75^{30}=(5*15)^{30}=5^{30}*15^{30}

Substituting these values in our division problem we will get,

\frac{3^{45}*15^{45}*15^{15}}{5^{30}*15^{30}}

Using power rule of exponents a^m*a^n=a^{m+n} we will get,

\frac{3^{45}*15^{45+15}}{5^{30}*15^{30}}

\frac{3^{45}*15^{60}}{5^{30}*15^{30}}

Using quotient rule of exponent \frac{a^m}{a^n}=a^{m-n} we will get,

\frac{3^{45}*15^{60-30}}{5^{30}}

\frac{3^{45}*15^{30}}{5^{30}}

Using product rule of exponents (a*b)^n=a^n*b^n we will get,

\frac{3^{45}*(3*5)^{30}}{5^{30}}

\frac{3^{45}*3^{30}*5^{30}}{5^{30}}

Upon canceling out 5^{30} we will get,

3^{45}*3^{30}

Using power rule of exponents a^m*a^n=a^{m+n} we will get,

3^{45+30}

3^{75}

Therefore, our resulting quotient will be 3^{75}.

8 0
3 years ago
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