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Bumek [7]
4 years ago
6

Please help - brainliest plus 20 points

Mathematics
1 answer:
EastWind [94]4 years ago
3 0

Answer:

{(–3, 2), (–2, 1), (3, 3), (3, –1)}

Step-by-step explanation:

You just have to figure out where each points go.

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-7x+5+8x&gt;3<br> How to do this?
Ymorist [56]
First, make it easy for yourself by putting like terms together
-7x+8x+5>3
then, combine like terms
-7x+8x=1x
now you have this
1x+5>3

hope this helps!
7 0
3 years ago
Read 2 more answers
Pencil cost 9p each.how much would 28 pencil cost
Akimi4 [234]

Answer:

3

Step-by-step explanation:

9 times 3 is 28

5 0
4 years ago
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On the plane curve defined by the parametric equations below, what point corresponds to t= -1
Anton [14]
The equation x=2t-1 represent the x-coordinate. To get the value of x, substitute t with -1.

That is:  x = 2(-1) - 1
                 = -2-1 
                = -3
Likewise, the equation y=t∧-3 represent the y-coordinate. Substituting t with -1,
 
  y = (-1)∧-3
    = -1

The point that correspond to t=-1 is (-3,-1).
6 0
3 years ago
Read 2 more answers
There are 7 students in a class. If there are 3 seats in the front row, how many ways can the students sit in the front row, ass
oksian1 [2.3K]

Answer:

<h2>35 different ways</h2>

Step-by-step explanation:

Since there are 7 students in a classroom to fill a front row containing 3 seats, we will apply the combination rule since we are to select 3 students from the total number of 7 students in the class.

In combination,<em> if r objects are to be selected from a pool of n objects, this can be done in nCr number of ways.</em>

<em>nCr = n!/(n-r!)r!</em>

Selecting 3 students from 7 students to fill the seats can therefore be done in 7C3 number of ways.

7C3 = 7!/(7-3)!3!

7C3 = 7!/(4)!3!

7C3 = 7*6*5*4!/4!*3*2

7C3 = 7*6*5/6

7C3 = 7*5

7C3 = 35

<em>Hence there are 35 different ways that the student can sit in the front assuming there are no empty seats.</em>

3 0
3 years ago
6k²+16k=0<br> x²-5x= 0<br> ANSWer these noeww!
pentagon [3]

Answer:

1) k = (-8)/5

2) x = 5

Step-by-step explanation:

1)

6 {k}^{2}  + 16k = 0

=  > 2k(3k + 8) = 0

=  > 3k + 8 =  \frac{0}{2k}  = 0

=  > 3k =  - 8

=  > k =  \frac{ - 8}{3}

2)

{x}^{2}   - 5x = 0

=  > x(x - 5) = 0

=  > x - 5 =  \frac{0}{x}  = 0

=  > x = 5

8 0
3 years ago
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