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shusha [124]
3 years ago
10

I need Predator and Prey population lab answer?

Biology
1 answer:
Bas_tet [7]3 years ago
8 0
Prey get eaten by predators
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Answer:

A base.

Explanation:

base+acid=neutral

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Which is the best explaination of a recessive gene?
Elanso [62]
Answer: A gene that is hidden or not expressed.
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Dalits are followed enters in temples true or false<br>​
makkiz [27]

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False A notice by the priest told dalits they can’t enter the temple because they are “not pure”

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2 years ago
A color-blind (X-linked recessive) human with Klinefelter syndrome has parents both of whom have normal color vision. 4a. From w
sineoko [7]

The extra X chromosome is received from mother.

<h3><u>Explanation</u>:</h3>

Klinefelter's syndrome is the condition of chromosomal aberration where the person has an extra X chromosome. This means the genotype of the person is 44+XXY and the total chromosome number is 47. This condition is achieved due to inappropriate meiotic division and one of the sperm or ovum has the an extra X chromosome.

Here both the parents are normal in terms of colour vision. So the father cannot have the gene of colour blindness because if it was present, then father would have been colour blind because he has only one X chromosome per cell. So its present in mother who is heterozygous in terms of colour blind gene. So the extra X chromosome also came from her which made the presence of two defective X chromosomes in the offspring and made it colour blind.

5 0
3 years ago
Use the information from Parts B and C to solve this problem. If a rabbit of genotype AaBb is bred to a rabbit of genotype AaBb,
Kipish [7]

The question is incomplete and the complete question is

Suppose that ear length in rabbits is controlled by two additive genes, each of which has two alleles. A true-breeding female (aabb) with 6-cm ears is mated to a true-breeding male (AABB) with 16-cm ears.

Answer:

AABb or AaBB

Explanation:

We know that,

aabb genotype - 6 cm

AABB genotype- 16-cm

To calculate the length of earlobe contributed by each allele in a genotype is :

1. length of aabb/4 or 6/4= 1.5 cm (a and b contribute for 1.5 cm each)

2. Length of AABB/4 or 16/4= 4 cm (A and B contribute for 4 cm each)

Now to have the earlobe to be 13.5 cm long then the genotype must be

13.5 = 4+4+4+1.5 or A+A+B+b or A+a+B+B

Therefore, the genotype will be-either AABb or AaBB

3 0
3 years ago
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