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Answer:
0.6672 is the required probability.
Step-by-step explanation:
We are given the following information in the question:
Mean, μ = 8.4 minutes
Standard Deviation, σ = 3.5 minutes
We are given that the distribution of distribution of taxi and takeoff times is a bell shaped distribution that is a normal distribution.
According to central limit theorem the sum measurement of n is normal with mean and standard deviation
Sample size, n = 37
Standard Deviation =
P(taxi and takeoff time will be less than 320 minutes)
Calculation the value from standard normal z table, we have,
0.6672 is the probability that for 37 jets on a given runway, total taxi and takeoff time will be less than 320 minutes.