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Evgen [1.6K]
3 years ago
11

56. In the periodic table, how many elements are found in each of

Chemistry
1 answer:
FrozenT [24]3 years ago
7 0
A) 6
b) 6
c) 14
d) 40
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Compare the relative strength of intermolecular forced in solids liquids and gases
DIA [1.3K]

Answer:

Intermolecular forces are weaker attractions that hold molecules or noble gas particles close together when they are in a liquid or solid form.

Explanation:

3 0
4 years ago
Is water made of plant cells or animal cells<br> •plant<br> •animals<br> •niether
Pepsi [2]

Answer:

i think niether

Explanation:

5 0
3 years ago
Which statements describe abiotic factors in an environment? Check all that apply.
olga nikolaevna [1]

Soil retains water and nutrients.

Several rocks rest in a stream.

Clouds create shade that changes temperatures

Abiotic factors are non-living components in the environment, or rather components in the environment that are not derived from life.

Explanation:

Abiotic factors interact with biotic factors to create ecoystems. An example of biotic factors interacting with abiotic factors include plants utilizing sunlight for photosynthesis and a wild beast drinking water form a watering hole in the middle of the savanna.

Learn More:

For more on biotic and abiotic factors check out;

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4 0
3 years ago
Read 2 more answers
For a particular reaction at 298 K, the equilibrium constant is equal to 581. Determine ΔG° in kJ/mol for the reaction. Do not i
slava [35]

<u>Answer:</u> The standard Gibbs free energy of the reaction is -15.8 kJ/mol

<u>Explanation:</u>

Relation between standard Gibbs free energy and equilibrium constant follows:

\Delta G^o=-RT\ln K_{eq}

where,

\Delta G^o = Standard Gibbs free energy = ?

R = Gas constant = 8.314J/K mol

T = temperature = 298 K

K_{eq}  = equilibrium constant = 581

Putting values in above equation, we get:

\Delta G^o=-(8.314J/Kmol)\times 298K\times \ln (581)\\\\\Delta G^o=-15769.13J/mol=-15.8kJ/mol

Conversion factor used: 1 kJ = 1000 J

Hence, the standard Gibbs free energy of the reaction is -15.8 kJ/mol

4 0
3 years ago
A 250mL sample of oxygen is collected over water at 30 C and 850 torr pressure. What is the pressure of the dry gas alone?
3241004551 [841]

Answer:

p_O=818.2torr

Explanation:

Hello there!

In this case, according to the given equation, it is possible to calculate the mass of oxygen by using the Dalton's law, considering that the total pressure is 850 torr and the vapor pressure of water at 30°C is 31.8 torr:

P_T=p_O+p_{H_2O}

Thus, we solve for the pressure of oxygen as follows:

p_O=P_T-p_{H_2O}\\\\p_O=850torr-31.8torr\\\\p_O=818.2torr

Best regards!

6 0
3 years ago
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