Answer:
19 g
Explanation:
Data Given:
Sodium Chloride (table salt) = 50 g
Amount of sodium (Na) = ?
Solution:
Molecular weight calculation:
NaCl = 23 + 35.5
NaCl = 58.5 g/mol
Mass contributed by Sodium = 23 g
calculate the mole percent composition of sodium (Na) in sodium Chloride.
Since the percentage of compound is 100
So,
Percent of sodium (Na) = 23 / 58.5 x 100
Percent of sodium (Na) = 39.3 %
It means that for ever gram of sodium chloride there is 0.393 g of Na is present.
So,
for the 50 grams of table salt (NaCl) the mass of Na will be
mass of sodium (Na) = 0.393 x 50 g
mass of sodium (Na) = 19 g
Answer:
0.683 moles of the gas are required
Explanation:
Avogadro's law relates the moles of a gas with its volume. The volume of a gas is directely proportional to its moles when temperature and pressure of the gas remains constant. The law is:
V₁n₂ = V₂n₁
<em>Where V is volume and n are moles of 1, initial state and 2, final state of the gas.</em>
<em />
Computing the values of the problem:
1.50Ln₂ = 5L*0.205mol
n₂ = 0.683 moles of the gas are required
<em />
The number of moles of one substance given the amount in mass can be calculated by the use of the molar mass. This is the mass of a compound per 1 mol of the said substance. For, KCl the molar mass is 74.55 g/ mol
148 g / 74.55 g/mol = 2 mol KCl
Hope this answers the question. have a nice day.
Answer:
In order to find the molecular formula from an empirical formula you must find the ratio of their molecular masses.
We know that the molecular mass of the molecule is 70
gmol-1
. We can calculate the molar mass of
CH2
from the periodic table:
C=12.01
gmol−1
H=1.01
gmol−1
CH2 =14.03
gmol−1
Hence we can find the ratio:
14.03
70
≈
0.2
Answer:
15
Explanation:
Magnesium Acetate Mg(C2H3O2)2
Number of atoms:
Carbon = 4
Hydrogen = 6
Magnesium = 1
Oxygen = 4
Total = 15
