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NeTakaya
3 years ago
6

The sales tax is 5% and you also have to leave a 15% tip, the meal is 15$ what would the cost be after the tip and tax

Mathematics
1 answer:
vfiekz [6]3 years ago
8 0

Answer: $18

Step-by-step explanation:

5% + 15% = 20%

20%/100 = 0.20

0.20 * 15 = 3

3 + 15 = 18

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At a hockey game, a vendor sold a combined total of 148 sodas and hot dogs. The number of sodas sold was three times the number
AleksandrR [38]

Answer:

37 hot dogs and 111 sodas

Step-by-step explanation:

148 divided by 4= 37

148 - 37= 111

if the number of sodas was three times it would have to be broken up into three groups making the hot dogs 37 and sodas three times the amout would be 111. hope this helped sorry for any spelling mistakes

3 0
2 years ago
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250 calls in 10 hours = _ calls in 15 hours
ipn [44]
250 calls in 10 hours = 375 in 15 hours
5 0
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The radius of a sphere is increasing at a rate of 5 mm/s. How fast is the volume increasing (in mm3/s) when the diameter is 40 m
jeka94

9514 1404 393

Answer:

  8000π mm^3/s ≈ 25,133 mm^3/s

Step-by-step explanation:

The rate of change of volume is found by differentiating the volume formula with respect to time.

  V = 4/3πr^3

  V' = 4πr^2·r'

For the given numbers, this is ...

  V' = 4π(20 mm)^2·(5 mm/s) = 8000π mm^3/s ≈ 25,133 mm^3/s

_____

<em>Additional comment</em>

By comparing the derivative to the area formula for a sphere, you see that the rate of change of volume is the product of the area and the rate of change of radius. This sort of relationship will be seen for a number of different shapes.

4 0
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These two polygons are similar. ​
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4 0
2 years ago
Actual lengths of pregnancy terms for a particular species of mammal are nearly normally distributed about a mean pregnancy leng
HACTEHA [7]

Solution :

The data is normally distributed.

The standard deviation is 18 days

Here the data is normally distributed and 54 days is 3 days of standard deviation.

Therefore, the percentage of the births that would be \text{expected to occur} within the 54 days of the mean \text{pregnancy} length is given by :

= P( -3 < Z < 3)

= 0.9544

= 95 %

Therefore, about 95% of the births would be \text{expected to occur} within 54 days of the men \text{pregnancy} length.

8 0
2 years ago
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