1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Hatshy [7]
2 years ago
10

The body of a 154-pound person contains approximately 2×10^2 milligrams of gold and 6×10^3 milligrams of aluminum. Based on this

information, the number of milligrams of aluminum in the body is how many times greater than the number of milligrams of gold in the body?
can you show your work too?
re asked it cs some bozo stole my points but pls hellp asap
Mathematics
1 answer:
hram777 [196]2 years ago
3 0

Answer:

2x10^2 and 6x 10^

Step-by-step explanation:

Hope I helped UwU

You might be interested in
WILL MARK BRAINLIST!!!!!!!!!!<br> |a+x|/ 2 − |a−x|/ 2 if a=−2; x=−6
blagie [28]
If those lines are absolute value then the answer is 0 if they are supposed to be parenthesis then the answer is -6
7 0
3 years ago
Read 2 more answers
64 is 4 times the difference between Sarah's age, aaa, and 44. Assume Sarah is older than 44. How would I write this as an equat
jeka94

Answer:

4(aaa - 44) = 64

Step-by-step explanation:

I think this is right.

4 0
3 years ago
Two trains start from Fort Worth traveling at the same speed. The trip for Train W takes 20 hours, while the trip for Train Z ta
MrMuchimi

Answer:

The equation that best models this situation is :

b. \frac{x}{20}=\frac{x+400}{25}

Distance traveled by Train W = 1600 miles

Distance traveled by Train Z = 2,000 miles

Step-by-step explanation:

Given:

Time taken for Train W to complete a trip = 20 hours

Time taken for Train Z to complete a trip = 25 hours

The city Train Z is traveling to is 400 miles farther away than the city Train W is traveling to.

both trains have same speeds and start from same location.

To find the distance in total each train travels.

Solution:

<em>Let length of the trip of Train W be </em>= x miles

Speed of Train W can be given as :

⇒ \frac{Distance}{Time}

⇒ \frac{x}{20}\ miles/h

<em>So, the length of the trip of Train Z will be</em> = (x+400) miles

Speed of Train Z can be given as :

⇒ \frac{Distance}{Time}

⇒ \frac{x+400}{25}\ miles/h

Since the speeds are same, so the equation to find x can be given as:

⇒ \frac{x}{20}=\frac{x+400}{25}

Solving for x

Multiplying both sides by 100 to remove fractions.

⇒ 100\times \frac{x}{20}=100\times \frac{x+400}{25}

⇒ 5x=4(x+400)

Using distribution.

⇒ 5x=4x+1600

Subtracting both sides by 4x

⇒ 5x-4x=4x-4x+1600

⇒ x=1600

Thus, Distance traveled by Train W = 1600 miles

Distance traveled by Train Z = 1600+400 = 2,000 miles

3 0
3 years ago
Can someone help out (; plz
zubka84 [21]

Answer:

2

Step-by-step explanation:

8 0
3 years ago
1 BAJILLION POINTS!!
Natalija [7]

Answer:

False!

Step-by-step explanation:

As C is not equal to -13 (number line)

So, your answer would be false.

hope it helps!

4 0
3 years ago
Read 2 more answers
Other questions:
  • Complete the steps for having the quadratic formula using the following ax^2+bx+c=0
    9·1 answer
  • Easy points scored<br><br><br> Hints<br> PCM=35<br> APC is not equal to 105, 35
    9·1 answer
  • What is 802.06 in expanded form
    12·2 answers
  • Write the equation of the line the that is parallel to 21x-7y=12 and goes through the point (1, -3).
    10·1 answer
  • PLEASE HELP ME!!  i have to answer this question fast please help
    9·1 answer
  • Mrs Shepard rode her bike 5.25 miles in 0.7 hours how fast was she going in miles per hour
    6·1 answer
  • Find the 60th term of the sequence below. 3, 7, 11, 15...​
    5·1 answer
  • A bakery sold a total of 400 cupcakes in a day, and 144 of them were vanilla flavored. What percentage of cupcakes sold that day
    8·1 answer
  • Ill give brainliest
    8·1 answer
  • Tomic calculated incorrectly that they had scored 5012 points. Select the possible reason for his error.
    5·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!