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algol13
3 years ago
10

Wind resistance ___as speed increase.

Physics
1 answer:
chubhunter [2.5K]3 years ago
6 0

Answer:

increases dramatically

Explanation:

due to resistance tends to prevent the motion of a body. When speed increases, the particles of air are set into motion and this energizes them. More air gains increased acceleration and they collide with a body. This initiates a resistance against the motion of such body. for instance, wind resistance increases rapidly as speed increases.

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In the drawing, water flows from a wide section of a pipe to a narrow section. In which part of the pipe is the volume flow rate
guapka [62]

Answer:

Volume flow rate is the same in both sections of the pipe

Explanation:

7 0
3 years ago
Radio waves travel at the speed of light. What is the wavelength of a radio signal with a frequency of 9.45 x 10^7 Hz?
Klio2033 [76]

Answer:

So I never really knew you

God, I really tried to

Blindsided, addicted

Felt we could really do this

But really I was foolish

Hindsight, it's obvious

Explanation:

3 0
3 years ago
What is the approximate uncertainty in the area of a circle of radius 4.5×10^4 cm? Express your answer using one significant fig
Igoryamba

Answer:

A=6.36\times 10^5\ m^2

Explanation:

It is given that,

Radius of the circle, r=4.5\times 10^4\ cm=4.5\times 10^2\ m

The area of the circle is given by :

A=\pi r^2

A=\pi (4.5\times 10^2\ m)^2

A=636172.51\ m^2

or

A=6.36\times 10^5\ m^2

As there is no uncertainty given in the radius of the circle. So, the area of the circle is 6.36\times 10^5\ m^2. Hence, this is the required solution.

5 0
4 years ago
a proton travelling along is x-axis is lowed by a niform electric field E. at x = 20.0 cm, the proton has a speed of 3.5x10^6 m/
anzhelika [568]

Answer:

Magnitude of electric field is 1.06 x 10^5 V/m along negative X-direction

Explanation:

Given: initial velocity of proton = u = 3.5 x 10^6 m/s

final velocity of proton = v = 0 m/s

initial point l_i = 0.2 m and final point is l_f = 0.8 m

According to conservation of energy:

change in in kinetic energy = change in potential energy of proton

⇒\frac{m}{2}(v^2-u^2 ) = qE(l_i - l_f)

where q and m is the charge and mass of proton E is the electric field , l_i and l_f is the initial and final position of proton

on substituting the respected values we get,

1.023 x 10^-^1^4 = 9.6 x 10^-^2^0 x E

⇒ E = 1.06 x 10^5 V/m

external force is opposite to the motion as velocity of proton decreases with distance.

Therefore, magnitude of electric field is 1.06 x 10^5 V/m along negative X-direction

5 0
3 years ago
Who else thinks brainly is dry
sleet_krkn [62]

Answer:

kinda

Explanation:

can i have brainlyest pls?

7 0
3 years ago
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