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xz_007 [3.2K]
3 years ago
6

Thermal escape of an atmosphere is most pronounced on worlds where the gravity is low and the temperature is high.

Physics
1 answer:
Alona [7]3 years ago
7 0
The answer is false
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Height of cannon 5 m, initial speed of projectile 15m/s, angle of launch 0 degrees. What is the range and time in the air? Pleas
Westkost [7]

Answer:

<em>The range is 15.15 m and the time in the air is 1.01 s</em>

Explanation:

<u>Horizontal Motion</u>

When an object is thrown horizontally (with angle 0°) with a speed v from a height h, it follows a curved path ruled exclusively by gravity until it eventually hits the ground.

The range or maximum horizontal distance traveled by the object can be calculated as follows:

\displaystyle d=v\cdot\sqrt{\frac  {2h}{g}}

To calculate the time the object takes to hit the ground, we use the equation below:

\displaystyle t=\sqrt{\frac{2h}{g}}

The cannon is shot from a height of h=5 m with an initial speed of v=15 m/s. The range is calculated below:

\displaystyle d=15\cdot\sqrt{\frac  {2*5}{9.8}}=15*1.01

d = 15.15 m

The time in the air is:

\displaystyle t=\sqrt{\frac{2*5}{9.8}}

t = 1.01 s

The range is 15.15 m and the time in the air is 1.01 s

8 0
3 years ago
What happens to parallel light rays that strike a concave lens?
zhenek [66]
Due to the shape of the lens , parallel rays will be deviated
5 0
3 years ago
Read 2 more answers
Which of the following must ALWAYS be equal to the buoyant force on an object?
professor190 [17]

Answer:

A

Explanation:

I’m not sure but I hope this helped

8 0
3 years ago
Heart cells must contract simultaneously to move blood.
krek1111 [17]

Answer:

<u>A</u>

Explanation:

The heart cells must contract simultaneously to move blood.

This means that it needs to act fast and efficiently.

Therefore, the connections among heart cells are characterized by :

  • having many branches
  • having many communicating junctions

The correct option should be <u>A</u>

4 0
2 years ago
Read 2 more answers
can somebody help me answer this question? A car went from 110 m/s to 80 m/s in 20 seconds. What was the acceleration of the car
gogolik [260]

Answer:

-1.5m/s²

Explanation:

Acceleration can be thought of as [Change in Velocity]/[Change in time]. To find these changes, you simply subtract the initial quantity from the final quantity.

So for this question you have:

  • V_i = 110m/s
  • V_f = 80m/s
  • t_i = 0s
  • t_f = 20s

which means that the acceleration = (80-110)/(20-0)[m/s²] = (-30/20)m/s² = -1.5m/s²

4 0
3 years ago
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