Question

A flexible chain weighing 40.0 N hangs between two hooks located at the same height (Fig. P12.17). At each hook, the tangent to the chain makes an angle θ =42.0° with the horizontal. Find (a) the magnitude of the force each hook exerts on the chain.

Answer 1

The magnitude of the force each hook exerts on the chain is 22.2N.

Solution:

Horizontal force on one half of the chain

$T_{e}$ cos 42° = $T_{m}$

$T_{e}$ sin 42° = 20

$T_{e}$  = 29.9N

Now,

$T_{m}$ = 22.2N

To learn more about the magnitude of forces, refer

brainly.com/question/20905151

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