We are given with a velocity-distance-time kinematic problem given the different times of two runners and is asked for the difference in distances the runner has ran in the track. we use the formula v= d/t where d is the distance of running, t is time and v is the velocity of the runner.
First runner,
v = d/t = 1000 m / (120+28.13s ) = 6.750826976 m/s
Second runner
Using the same velocity we determine d2.
v = d2/t2 = d2 / (120+28.48s) = 6.750826976 m/s ; d2 = 1002.362789
distance of running track is the difference of the two distance achieved by the runners, delta d= d2 - d = 2.362789 m
It would be 12W because: 6v is half of 12v so half of 24w would be 12w
Answer:
The angular acceleration of the top is 0.18 rad/s²
Explanation:
Given;
angular velocity of the top, ω = 16 rad/s
time it takes to come to a complete stop, t = 88.9s
The angular acceleration of the top, is calculated as;
α is the angular acceleration
ω is angular acceleration
t is the time
Therefore, the angular acceleration of the top is 0.18 rad/s²
Answer:
I think it depends on the purpose of using Gamma rays. It can be both good and bad
Answer:
0.5 m/s2
Explanation:
accelration formula : final velocty - starting velocity divided by time
