When an object moves its length contracts in the direction of motion. The faster it moves the shorter it gets in the direction of motion.
The object in this question moves and then stops moving. So it's length first contracts and then expands to its original length when the motion stops.
The speed doesn't have to be anywhere near the speed of light. When the object moves its length contracts no matter how fast or slow it's moving.
Answer:
A) in between Earth and the sun.
Explanation:
During this phase, the dark portion of the moon is facing Earth, so the moon is not visible in the night sky.
The chemical symbol used is 2K + 2I to complete the equation for the decomposition reaction.
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What is decomposition reaction?</h3>
Decomposition reaction is defined as a chemical reaction when the reactant or molecule breaks down into less complex compounds Consequently, when a single reactant splits into two or more products. Because two or more reactants are combined to create a single product in a combination reaction, they are known as the opposite of a combination reaction.
One reactant produces two or more products during a decomposition process. Iodine and potassium will be produced as potassium iodide breaks down. With two K and two I on each side, this equation is balanced. It can be described using the all-inclusive formula: AB --> A + B.
Thus, the chemical symbol used is 2K + 2I to complete the equation for the decomposition reaction.
To learn more about decomposition reaction, refer to the link below:
brainly.com/question/8009068
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Complete Question
The complete question is shown on the first uploaded image
Answer:
The distance is
Explanation:
From the question we are told that
The size of Jupiter is
The length of the International Space Station is
The size of the International Space Station is
The angular size where the same one night and this angular size is mathematically represented as
Since is constant
substituting values
=>
Now we are told to convert to AU and 1 AU
So
Answer:
The coordinates of the target are (8790m, 3400m).
Explanation:
First of all, we have to find the components of the initial velocity and , using trigonometry:
Now, we find the x-coordinate using the equation of motion with constant speed (since there is no external force in x-axis that causes an horizontal acceleration):
Then, we find the y-coordinate using the equation of position of an object with constant acceleration (since there is the gravitational force causing a vertical acceleration on the shell):
Finally, the coordinates of the target are (8790m, 3400m).