Answer:
Explanation:
Image formation by objective lens ,
f = focal length of objective = .75 cm, ( positive )
object distance u = .81 cm ( negative )
v = image distance
1/v - 1/u = 1/f
1/v + 1/.81 = 1 / .75
1/v = 1/ .75 - 1/.81 = .098765
v = 10.125.cm
Image formation by eye piece,
v = infinity ( for relaxed eye )
f ( eye piece ) = 2.70cm
u = ?
1/v - 1/u = 1/f
0 -1/u = 1/2.7
u = 2.7 cm
Total length between lenses
= 2.7 + 10.125
= 12.825 cm
Total magnification = m₁ x m₂
m₁ is magnification by objective and m₂ is magnification by eye piece
m₁ = v/u = 10.125 / .810 = 12.5
m₂ = 1 + D / f = 1 + 25 / 2.7 = 10.25
Total magnification
= 12.5 x 10.25 = 128.125
It <span>is to metabolize or break down carbohydrates and fatty acids in order to generate energy.</span>
Answer: a) 335.8 μm; b) keeping the same radius, the new has double potential, V=1340V so if teh radius is also double the potentail is the same (V=670V).
Explanation: In order to explain this problem we have to consider the potential given for sphere respect to infinity ( V=0) in the form:
V=k*Q/R the we have
R=k*Q/V= 9*10^9*25*10^-12/670=335.8 *10^-6 m
When two drop join to form a single drop (considering with the same radius) we have:
V=k*2Q/R
So the new V is double the original,
V=9*10^9*2*25*10^-12/335.8*10^-6=1340V
if the final single drop has a 2R of radius so
V=k*2Q/2R= 670 V
It has the same original potential.
Motion occurs because a force per it into action