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3 years ago

The system of equations graphed below has how many solutions?

Mathematics

1 answer:

Artist 52 [7]3 years ago

5 0

Answer: C) 0

The lines are parallel. They never cross. To have a solution, the lines need to intersect. Each intersection is a solution. That's why there are no solutions here. The system is inconsistent.

Note how the slopes are both 1/2 while the y intercepts are different. Parallel lines have equal slopes but different y intercepts.

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A water skiing jump is 4.6m long. It rises 1.1m. What

lorasvet [3.4K]

The inclination to the nearest tenth of a degree exists 0.24146

<h3>What is the inclination to the nearest tenth of a degree?</h3>

The given scenario includes a right-angled triangle where the length of the ramp exists hypotenuse and the rise of ramp exists the perpendicular.

Given: H = 4.6 m and P = 1.1 m

We have to use the trigonometric ratios to find the angle. The ratio that has to be used should involve both perpendicular and hypotenuse

Let x be the angle then

sin x = P/H

sin x = 1.1/4.6

sin x = 0.23913

$$$sin^{-1} x$ = 0.24146

The inclination to the nearest tenth of a degree exists 0.24146

To learn more about trigonometric ratios refer to:

brainly.com/question/14033725

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1 year ago

Find the perimeter of pentagon STUVW WITH VERTICES S(0,0) T(3,-2) U(2,-5) V(-2,-5) W(-3,-2)

andrew11 [14]

Use the distance formula.

$\sqrt{( x_{2} - x_{1} )^2 + (y_{2} - y_{1})^2}$

Points S and W.
$\sqrt{(3)^2 + (2)^2}$

$\sqrt{9+4}$

$\sqrt{13}$

~3.6

Points S and T
$\sqrt{(3 - 0)^2 + (-2 - 0)^2}$

$\sqrt{(3)^2 + (-2)^2}$

$\sqrt{9+4}$

$\sqrt{13}$

~3.6

Points T and U
$\sqrt{(3 - 2)^2 + (-2 + 5)^2}$

$\sqrt{(1)^2 + (3)^2}$

$\sqrt{1+9}$

$\sqrt{10}$

~3.1

Points U and V
$\sqrt{(2+2)^2 + (-5 + 5)^2}$

$\sqrt{(4)^2 + (0)^2}$

$\sqrt{16}$

~4

Points V and W
$\sqrt{(-2+3)^2 + (-5 + 2)^2}$

$\sqrt{(1)^2 + (-3)^2}$

$\sqrt{2+9}$

$\sqrt{11}$

~3.3

Add all these together.

3.3 + 3.1 + 4 + 3.1 + 3.6
≈17

4 0

4 years ago

The population of Chicago, Illinois, in 2003 was 2,869,121. The area of Chicago was 227.1 square miles. What was the average num

ValentinkaMS [17]

Answer:

12,633.7

Step-by-step explanation:

population of Chicago, in 2003 = 2,869,121

The area of Chicago = 227.1 square miles.

What was the average number of people living in 1 square mile?

Average number of people living in 1 square mile also refers to the population density of Chicago

Average number of people living in 1 square mile = Total population / total square miles