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shtirl [24]
3 years ago
8

PLEASE HELP ME QUICK PLEASE

Mathematics
1 answer:
Vikentia [17]3 years ago
3 0

Answer:

34

Step-by-step explanation:

in the photo illustrated

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Andrei [34K]

Answer:

option 3 is correct

Step-by-step explanation:

because ....

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Please help me!! pel​
nikdorinn [45]

Answer:

5

Step-by-step explanation:

plug that bad boy in and chug

(-6)^{2} + 6(-6) +5

36 + (-36) + 5

36 - 36 + 5

5

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3 years ago
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Joe the trainer has two solo work out plans That he offers his clients. Plan A and Plan B. Each client does either one or the ot
Zinaida [17]

Answer: plan A lasts for 0.5 hour. Plan B lasts for 0.75 hour.

Step-by-step explanation:

Let x represent the duration of plan A.

Let y represent the duration of plan B.

On Friday there were 3 clients who did plan A and 2 who did Plan B.

Joe trained his Friday clients for a total of 3. It means that

3x + 2y = 3- - - - - - - - - -1

On Saturday there were 5 clients who did plan A and 6 who did plan B. Joe trained his Saturday clients for a total of 7 hours. It means that

5x + 6y = 7- - - - - - - - - 2

Multiplying equation 1 by 5 and equation 2 by 3, it becomes

15x + 10y = 15

15x + 18y = 21

Subtracting, it becomes

- 8y = - 6

y = - 6/-8

y = 0.75

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3x + 1.5 = 3

3x = 3 - 1.5 = 1.5

x = 1.5/3

x = 0.5

3 0
3 years ago
The volume of a cone varies jointly as the height of the cone and the area of the base. The volume of a cone with height 30 cent
irina [24]

Answer:

V₂=28cm³

Step-by-step explanation:

<u>Way 1</u>

The volume of a cone is V=\frac{\pi r^{2}h}{3},  and  h₁ = 30 cm but the base (Ba₁) is 14 cm², so

V=\frac{Ba.h}{3}, where Ba= Base area

if h₂=7cm and Ba₂=12cm² then

V_{1} =\frac{12cm^{2}.7cm}{3}=28cm^{3}

<u>Way2</u>

If the volume of a cone varies jointly as the height of the cone and the area of the base, then we must find the relationship between the bases and heights of the cones

Ba₁*h₁ = 30cm*14cm² = 420cm³

Ba²*h²=   7cm*12cm² =   84cm³

420/84 = 5; ratio = 5 also

V₂=V₁/5 ⇒ V₂=140cm³/5 = 28cm³

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Find the equivalent exponential expression. (72)3
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