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babymother [125]
3 years ago
6

1. Find the value of x. 55° (4x - 5)° O 26 O

Mathematics
1 answer:
Paha777 [63]3 years ago
7 0

Answer:

26

Step-by-step explanation:

The sum of angles in a triangle is 180 degrees, use this and set up an equation;

x + ( 4x -5 ) + 55 = 180

Simplify

x + ( 4x - 5 ) + 55 = 180

5x + 50 = 180

Inverse operations;

5x + 50 = 180

    -50     - 50

5x = 130

/5    /5

x = 26

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A trapezoid has an area of 13.5 square inches. If the bases are 3 and 6 inches what is the height?
liraira [26]
Well the formula is : b1+b2/2 (h)

so the height would be solved as : 
13.5 = 3+6/2 (h)
13.5 = 9/2 (h)
h = (13.5)/(9/2)
h = (13.5) x (2/9)  *reciprocal*
h = (27) / (9)
h = 3


5 0
3 years ago
Please help me with this math problem
elena55 [62]

When a tangent line (13.5 cm) and a secant (lines x + 8.45 cm) intersect then:


tangent line^2 = 8.45 * (8.45 + x)


13.5^2 = 71.4025 + 8.45 x


182.25 -71.4025 = 8.45x


8.45 x = 110.8475


x = 13.1180473373


x = 13.1 (rounded)


Source:

1728.com/circangl.htm




4 0
3 years ago
Algebra 1
SVETLANKA909090 [29]

Answer:

-3/7

Step-by-step explanation:

slope = (y2-y1)/ (x2-x1) = 4-1/3-10 = 3/-7

8 0
3 years ago
Which transformation of a figure will create an image that is not congruent to the
sattari [20]

Answer:B

Step-by-step explanation:because I got it correct

3 0
3 years ago
Please help will give brainliest.
Viefleur [7K]

Answer:

D

Step-by-step explanation:

a is false since x could be 0.

b is easy to check, just plug numbers in, and we can see that it's false(you would get 0+0=1 and -0-0=-1 once plugged in)

c is also easy to check, just plot the line or simplify the first equation. since (2x+2y)/2=4/2 is also x+y=2, the second equation is also x+y=2, so it must have infinitely many solutions.

d must be true due to process of elimination but let's check to make sure.

7y=14x, divide both sides by 7 to get y=2x and since they're the same equation it must mean that they have infinitly many solutions and we can see that it is correct

4 0
3 years ago
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