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SSSSS [86.1K]
3 years ago
5

2/5 + r = 1 and 4/5 What is r?

Mathematics
1 answer:
MariettaO [177]3 years ago
7 0
Answer- r= 7\5 hope this helps!!
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What is the equation for the line? Enter your answer in the box
Ipatiy [6.2K]

y=-1/2x-4

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3 years ago
Find the measure of each angle indicated.​
Brilliant_brown [7]

Answer:

90 degrees

Step-by-step explanation:

Sum of the angles in a triangle = 180°

Opposite angles are equal

For two parallel lines and a transversal,

corresponding angles are equal, and

alternate angles are equal.

45+45=90.

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Plus, you can see that the angle forms a perfect 90 degree angle.

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3 years ago
2248/98 as a mix fraction?
Anarel [89]
The answer is 22 46/49 
Answer:
= 2248/1 ÷ 98/1

= (2248 × 1) / (98 × 1)

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3 years ago
A random sample of 5200 permanent dwellings on an entire reservation showed that 1571 were traditional hogans.
quester [9]
P^ = 1571/5200 = 0.3021

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4 0
3 years ago
Read 2 more answers
ASAP!!! Use the pythagorean theorem to prove that the point (√2/2, √2/2) lies on the unit circle. I need setup, explination, ans
docker41 [41]

Answer:

In brief, apply the pythagorean theorem to show that the distance between the point (\sqrt{2}/2,\sqrt{2}/2) and the origin is 1.

Step-by-step explanation:

The pythagorean theorem can give the distance between two points on a plane if their coordinates are known.

A point is on a circle if its distance from the center of the circle is the same as the radius of the circle.

On a cartesian plane, the unit circle is a circle  

  • centered at the origin (0,0)
  • with radius 1.

Therefore, to show that the point (\sqrt{2}/2,\sqrt{2}/2) is on the unit circle, show that the distance between (\sqrt{2}/2,\sqrt{2}/2) and (0,0) equals to 1.

What's the distance between (\sqrt{2}/2,\sqrt{2}/2) and (0,0)?

\displaystyle \sqrt{\left(\frac{\sqrt{2}}{2}-0}\right)^{2} + \left(\frac{\sqrt{2}}{2}-0\right)^{2}} = \sqrt{\frac{1}{2} + \frac{1}{2}}= \sqrt{1}= 1.

By the pythagorean theorem, the distance between (\sqrt{2}/2,\sqrt{2}/2) and the center of the unit circle, (0,0), is the same as the radius of the unit circle, 1. As a result, the point (\sqrt{2}/2,\sqrt{2}/2) is on the unit circle.

3 0
3 years ago
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