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777dan777 [17]
4 years ago
10

Neil has been running a tutoring business since 2005. He charges a monthly fee for weekly tutoring sessions and a phone help lin

e. Each year, he has increased his fee by the same amount. The table shows what Neil charged each customer for two given years of his business: Year Annual Tutoring Fee 2005 $1200 2008 $1350 A. What is the rate of change and initial value for Neil's business? How do you know? B. Write an equation in slope-intercept form to represent the fees that Neil charges each year.
Mathematics
1 answer:
aleksklad [387]4 years ago
8 0
Rate of change is the same as slope in this case.
(1350-1200)/(2008-2005) = 150/3 = $50 increase per year
The initial amount he started charging was $1200 a year.
y = 50x + 1200, where x represents the number of years since 2005.
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Answer:

Option 4 : 16+24i

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Radius = distance between two given points/2

=\frac{1}{2} \sqrt{(15+25)^2+(25+17)^2} \\=\frac{58}{2} \\=29

Let us calculate distance form each point.

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iv) 16+24i: distance from -5+4i= 29

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