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3 years ago

Imagine if adam sandler died:(

Mathematics

2 answers:

charle [14.2K]3 years ago

7 0

This would be horrible my favorite movie is big daddy, it’s a classic. i used to watch with my uncle all the time. it reminds me of him so much

kkurt [141]3 years ago

6 0

Answer:

its a good photo I would miss him so much if it was true

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A company sold 123 mobile phones for ₹ 8000 each. With the same money, 48 music systems were bought. Find the cost of one music

vova2212 [387]

Answer:

Step-by-step explanation:

123 X 8000 = 984000

984000/48 = 20500(PUT EURO SIGN)

6 0

3 years ago

How many year apart is 384 BC from 1952 AD

julsineya [31]

BC and BCE are Before Common Era
So what you want to do is add 1952 and 384
1952 + 384 = 2336
So the amount of years between 384 BC and 1952 AD is about 2,336 years
Hope this helps

6 0

3 years ago

Read 2 more answers

Train X is traveling at a constant speed of 30 miles per hour and Train Y is traveling at a constant speed of 40 miles per hour.

topjm [15]

Answer:

3.5 hours

Step-by-step explanation:

Speed of train X=30 mph

Speed of train Y=40 mph

Relative speed When the two trains travelling in same direction

Relative speed=40-30=10 mph

Total distance =25+10=35 miles

We have to find the time when train Y is 10 miles ahead of train X.

We know that

Time= $\frac{Distance}{Relative\;speed}$

Using the formula

Then, we get

Time= $\frac{35}{10}=3.5 hours$

Hence, it will be 3.5 hours until train Y is 10 miles ahead of train X.

7 0

3 years ago

Read 2 more answers

If sin 0=3/5, then cos 0=

vaieri [72.5K]

Answer:

$\frac{4}{5}$

Step-by-step explanation:

Given

sinΘ = $\frac{3}{5}$ = $\frac{opposite}{hypotenuse}$

Then the hypotenuse = 5 and one leg of the right triangle is 3

Using Pythagoras' identity to find the second leg (x)

x² + 3² = 5²

x² + 9 = 25 ( subtract 9 from both sides )

x² = 16 ⇒ x = 4

cosΘ = $\frac{adjacent}{hypotenuse}$ = $\frac{4}{5}$

7 0

2 years ago

Write the expression as a single logarithm

vredina [299]

$3\log_7y + 4(\log_7x - 5\log_7z)\\\log_7y^{3} + 4(\log_7x - 5\log_7z)\\\log_7y^{3} + 4(\log_7x - \log_7z^{5})\\\log_7y^{3} + 4(\log_7(\frac{x}{z^{5}}))\\\log_7y^{3} + \log_7(\frac{x}{z^{5}})^{4}\\\log_7(y^{3} \times (\frac{x}{z^5{5}})^{4})$

4 0

3 years ago