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3 years ago

How do I answer this question I don’t understand it

Mathematics

2 answers:

Phoenix [80]3 years ago

6 0

Answer:

$u = -\dfrac{vx}{w}$

Step-by-step explanation:

You are allowed to multiply and divide both sides of an equation by the same non-zero number or non-zero variable. Do the appropriate operations to isolate the u.

$x = -\dfrac{1}{v}uw$

We are solving for u, so first, switch sides.

$-\dfrac{1}{v}uw = x$

Multiply both sides by v.

$-\dfrac{1}{v}uw \times v = x \times v$

$-uw = x \times v$

Divide both sides by -w.

$\dfrac{-uw}{-w} = \dfrac{xv}{-w}$

$u = -\dfrac{vx}{w}$

madam [21]3 years ago

5 0

Answer:

4. Tell your interviewer what you do know.

If you do have some knowledge of the question, then take the time to tell your interviewer what you do know of the situation. Saying everything out loud can start you on the process of figuring out the problem.

Step-by-step explanation:

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What is the volume of a right circular cylinder with a radius of 6 m and a height of 9 m?

geniusboy [140]

The volume of the right circular cylinder with a radius of 6 m and a height of 9 m is 1018 m².

The volume of a substance is the total space occupied by a three-dimensional object.

The volume of a right circular cylinder with a radius of r units and a height of h units is given by the formula V = πr²h square units.

We are asked to find the volume of the right circular cylinder with a radius of 6 m and a height of 9 m.

Substituting these values in the formula, we get Volume,

V = π(6)²(9) m² = 324π m² = 1017.876 m² ≈ 1018 m².

Therefore, the volume of the right circular cylinder with a radius of 6 m and a height of 9 m is 1018 m².

Learn more about volumes at

brainly.com/question/2965150

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6 0

2 years ago

Simplify: 6x3y2 (4x4 − 3xy)

Over [174]

The answer is going to be: (2•3x^4y^2) • (4x^3 - 3y)

^=The variable or number behind it is an exponent

8 0

3 years ago

Read 2 more answers

Select all of the transformations that could change the location of the asymptotes of a cosecant of secant function.

mars1129 [50]

We have to select all of the transformations that could change the location of the asymptotes of a cosecant of secant function.

So given function can be written as:

y=csc( sec(x))

First we need to determine the location of asymptote which is basically a line that seems to be touching the graph of function at infinity.

From attached graph we see that Asymptotes (Green lines) are vertical.

So Vertical shift or vertical stretch will not affect the location of asymptote because moving up or down the vertical line will not change the position of any vertical line.

only Left or right side movement will change the position of vertical asymptote. Which is possible in Phase shift and period change.

Hence Phase shift and Period change are the correct choices.

8 0

4 years ago

Read 2 more answers

If you run for 0.4 hours at 7 mph, how fast should you walk during the next 0.8 hours to have the average speed of 5 mph?

Orlov [11]

4mph

0.4 x 7 mph =2.8 miles - distance run.

Let the required speed =S

[2.8 + 0.8S] / [0.4+0.8] =5, solve for S

S =4 mph - must walk to attain an average of 5 mph, or:

6 miles / 1.2 hours =5 mph

8 0

4 years ago

Read 2 more answers

At what value of x does the graph of the following function F(x) have a

Free_Kalibri [48]

Answer:

Step-by-step explanation:

Given

f(x) = $\frac{1}{x+2}$

The denominator cannot be zero as this would make f(x) undefined.

Equating the denominator to zero and solving gives the value that x cannot be and if the numerator is non zero for this value then it is a vertical asymptote.

x + 2 = 0 ⇒ x = - 2

The equation of the vertical asymptote is x = - 2

6 0

3 years ago