Answer:
2sin(3θ) - √3 = 0
Step-by-step explanation:
sin(3θ) = √3/2
3θ = π/3 + 2kπ or 2π/3 + 2kπ, k = 0, ±1, ±2, ±3,...
θ = π/9 + 2kπ/3, 2π/9 + 2kπ/3
If k = 0, we get θ = π/9, 2π/9
If k = 1, we get θ = 7π/9, 8π/9
If k = 2, we get θ = 13π/9, 14π/9
Other values of k give values of θ lying outside of the interval [0, 2π).
The answer in the green box should be 9.
All way solve what’s in parentheses first!!!
