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Oliga [24]
3 years ago
11

Solve UW. how do I get the answer?

Mathematics
2 answers:
pshichka [43]3 years ago
8 0

Answer:

UW = 67

Step-by-step explanation:

UW = 6x - 35

VW = 4x - 20

UV = 19

So that means

4x - 20 + 19 = 6x - 35

4x - 1 = 6x - 35

-1 = 2x - 35

34 = 2x

x = 17

6(17) - 35

102 - 35 = 67

If my answer is incorrect, pls correct me!

If you like my answer and explanation, mark me as brainliest!

-Chetan K

solmaris [256]3 years ago
8 0

Answer:

Step-by-step explanation:

19 + ( 4x - 20 ) = 6x - 35

4x - 1 = 6x - 35

2x = 34

x = 17

<em>UW </em>= 6(17) - 35 <em>= 67</em>

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Bruno noticed today’s gasoline price at the local convenience store was advertised as $3.40 per gallon. This price is 15% above
Lisa [10]

Answer:

Last year’s price = $2.96

Step-by-step explanation:

Given:

Current price of gasoline = $3.40

Higher rate = 15%

Find:

Last year’s price

Computation:

Last year’s price = Current price of gasoline [100 / (100 + 15)]

Last year’s price = Current price of gasoline [100 / (115)]

Last year’s price = $3.40 [100 / (115)]

Last year’s price = 2.95652

Last year’s price = $2.96

3 0
4 years ago
The difference between objects being "similar" vs. "congruent
bija089 [108]

Answer: See below

Step-by-step explanation:

The difference between similar and congruent is the size and shape.

If two objects are similar, they look similar to each other, meaning they look the same, but not exactly the same. It can be 2 stuffed animals that look the same, but different sizes. One can be large and other can be small.

If two objects are comgruent, you know that they are EXACTLY the same. They are the same size, shape, etc. Using the example from above, you have either two large stuffed animals, or two small stuffed animals. The two large animals would be congruent to each other, same for the small animals.

7 0
3 years ago
Read 2 more answers
The velocity of a turtle is recorded at 1 minute intervals (in meters per second). Use the right-endpoint approximation to estim
aliina [53]

Answer:

The total distance that the turtle traveled during the 5 seconds recorded is Distance \:traveled\approx 3.838\:\frac{m}{s}

Step-by-step explanation:

To estimate distance traveled of an object moving in a straight line over a period of time, from discrete data on the velocity of the object, we use a Riemann Sum. If we have a table of values

\left\begin{array}{ccccccc}time\:=\:t_i&t_0=0&t_1&t_2&...&t_n\\velocity\:=\:v(t_i)&v(t_0)&v(t_1)&v(t_2)&...&v(t_n)\end{array}\right

where \Delta t=t_i-t_{i-1}, then we can approximate the displacement on the interval [t_{i-1},t_i] by v(t_{i}) \times\Delta t.

Therefore the distance traveled of the object over the time interval [0,t_n] can be approximated by

Distance \:traveled\approx |v(t_1)|\Delta t+|v(t_2)|\Delta t+...+|v(t_n)|\Delta t

This is the right endpoint approximation.

We are given a table of values for <em>v(t)</em>

\left\begin{array}{cccccccc}t(sec)&0&1&2&3&4&5\\v(t)&0.078&0.83&0.75&0.98&0.853&0.425\end{array}\right

Applying the right endpoint approximation formula we get,

\Delta t = 1\sec

Distance \:traveled\approx |v(t_1)|\Delta t+|v(t_2)|\Delta t+|v(t_3)|\Delta t+|v(t_4)|\Delta t+|v(t_5)|\Delta t\\\\Distance \:traveled\approx 0.83(1)+0.75(1)+0.98(1)+0.853(1)+0.425(1)\\\\Distance \:traveled\approx 3.838\:\frac{m}{s}

The total distance that the turtle traveled during the 5 seconds recorded is Distance \:traveled\approx 3.838\:\frac{m}{s}

4 0
3 years ago
Can someone help me???
Viktor [21]
Nicole sells 36 cupcakes for $ 2 each: 36 × 2 = 36(2) : B

Mikko divides his 8 - hour - long camp into 4 sessions of equal length: 8 ÷ 4 : C

Curtis has $ 36 and spends $ 2 : 36 - 2 : D

Darla shares 4 pounds of trail mix equally among 8 people : 4 ÷ 8 : A

8 0
3 years ago
Please help me What are the dimensions of the rectangle shown below? Remember to use the axes on the coordinate grid to help you
Deffense [45]
It’s 6 units x 4 units
6 0
4 years ago
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